我如何动态地在dropDownList中更改复选框基础的值

2024-04-26 • 问答

我有一个表单，需要将复选框更改为基于dropDownList的int选择选中或未选中。我是PHP和Yii2的初学者。

这是我的表格

<div class="npi-approval-review-form">

<?php if(!empty(Yii::$app->session->get('activity') && Yii::$app->session->get('activity')->need_signature == 'S'))$model->sign = 1; ?><?php ?>

    <?php $form = activeForm::begin(); ?>
        <table>
            <tbody>

            <tr>
                <td>
                    <?php if ($model->type == TypeOrigin::Aprovação): ?>
                    <?= $form->field($model,'status')->dropDownList(StatusReview::asArray(),['prompt'=>StatusApproval::asArray()[$model->status]]); ?>
                    <?php endif; ?>

                    <?php if ($model->type == TypeOrigin::Revisão): ?>
                        <?= $form->field($model,['prompt'=>StatusReview::asArray()[$model->status]]); ?>
                    <?php endif; ?>
                </td>

                <td>&nbsp;&nbsp;&nbsp;</td>

                <td>
                    <?= $form->field($model,'type')->textInput(['value'=>TypeOrigin::asArray()[$model->type],'readonly' => true,'disabled' => 'true']);?>
                </td>
            </tr>
            </tbody>
        </table>

        <?= $form->field($model,'conclusion')->textarea(['rows' => 5,'maxlength' => true]) ?>

        <?= $form->field($model,'sign')->checkBox(['value'=> $model->status == '2' ? '0' : '1']) ?>

        <div class="form-group">
            <?= Html::submitButton('Salvar',['class' => 'btn btn-success']) ?>
        </div>

    <?php activeForm::end(); ?>

</div>

<script> $("#select_id").on('change',function(){ // if dropdown with id select_id changed. var checkbox = $("#checkbox_id"); if($(this).val() === 'x'){ // set checkbox checked if option equal x checkbox.prop('checked',true); }else{ // else remove checked. checkbox.prop('checked',false); } }) </script>

我如何动态地在dropDownList中更改复选框基础的值

selectmy2009 回答：我如何动态地在dropDownList中更改复选框基础的值

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