使用Ajax实现异步交互的效果,使显示验证结果信息的时候没有页面刷新
改程序源代码如下:
- <%@ page language="java" import="java.util.*" pageEncoding="utf-8" contentType="text/html; charset=utf-8"%>
- <%
- String path = request.getContextPath();
- String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
- %>
- <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
- <html>
- <head>
- <base href="<%=basePath%>">
- <title>My JSP 'index.jsp' starting page</title>
- <Meta http-equiv="pragma" content="no-cache">
- <Meta http-equiv="cache-control" content="no-cache">
- <Meta http-equiv="expires" content="0">
- <Meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
- <Meta http-equiv="description" content="This is my page">
- <!--
- <link rel="stylesheet" type="text/css" href="styles.css">
- -->
- <script type="text/javascript">
- var XMLHttprequest = flase;
- function createXMLHttprequest() {
- if(window.XMLHttprequest){
- XMLHttprequest = new XMLHttpRequest();
- }
- else if(window.ActiveXObject){
- try {
- XMLHttprequest = new ActiveXObject("Msxm12.XMLHTTP");
- } catch (e) {
- try {
- XMLHttprequest = new ActiveXObject("Microsoft.XMLHTTP");
- } catch (e) {}
- }
- }
- }
- function sendRequest(url) {
- createXMLHttprequest();
- XMLHttprequest.open("GET",url,true);
- XMLHttprequest.onreadystatechange =processResponse;
- XMLHttprequest.send(null);
- }
- function processResponse() {
- if(XMLHttprequest.readyState==4){
- if(XMLHttprequest.status==200){
- var res = XMLHttprequest.responseText;
- window.alert(res);
- }
- }
- }
- function userCheck() {
- var username = document.myform.username.value;
- var password = document.myform.password.value;
- if(username==""){
- window.alert("用户名不能为空");
- document.myform.username.focus();
- return false;
- }
- else{
- sendRequest('log?username='+username+'&password='+password);
- }
- }
- </script>
- </head>
- <body>
- <form action="" name="myform">
- 用户名:<input type="text" name="username"/><br>
- 密码:<input type="text" name="password"/><br>
- <input type="button" value="登录" onclick="userCheck()"/>
- </form>
- </body>
- </html>
web.xml
- <?xml version="1.0" encoding="UTF-8"?>
- <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
- <display-name>AjaxTest</display-name>
- <welcome-file-list>
- <welcome-file>index.jsp</welcome-file>
- </welcome-file-list>
- <servlet>
- <servlet-name>msl</servlet-name>
- <servlet-class>action.LoginAction</servlet-class>
- </servlet>
- <servlet-mapping>
- <servlet-name>msl</servlet-name>
- <url-pattern>/log</url-pattern>
- </servlet-mapping>
- </web-app>
LoginAction.java
- package action;
- import java.io.IOException;
- import java.io.PrintWriter;
- import java.io.UnsupportedEncodingException;
- import javax.jms.Session;
- import javax.servlet.http.HttpServlet;
- import javax.servlet.http.HttpServletRequest;
- import javax.servlet.http.HttpServletResponse;
- import javax.servlet.http.HttpSession;
- public class LoginAction extends HttpServlet {
- protected void doGet(HttpServletRequest request,HttpServletResponse response) throws IOException {
- request.setCharacterEncoding("utf-8");
- String username = request.getParameter("username");
- String password = request.getParameter("password");
- response.setContentType("text/html; charset=utf-8");
- response.setHeader("Cache-Control","no-cache");
- PrintWriter out = response.getWriter();
- if(username.equals("admin")&&password.equals("admin")){
- System.out.println("1");
- out.println("热烈欢迎您");
- }else{
- out.println("对不起,登录失败!");
- }
- out.close();
- }
- protected void doPost(HttpServletRequest request,HttpServletResponse response) throws IOException{
- doGet(request,response);
- }
- }
核心内容就是将字符串写进response中,然后通过下面这部分javascript代码显示出来
- if(XMLHttprequest.readyState==4){
- if(XMLHttprequest.status==200){
- var res = XMLHttprequest.responseText;
- window.alert(res);
- }