public void onPopup(View view){final PopupMenu menu=new PopupMenu(this,view);menu.getMenuInflater().inflate(R.menu.menu1,menu.getMenu());menu.setOnMenuItemClickListener(new PopupMenu.OnMenuItemClickListener(){public boolean onMenuItemClick(MenuItem item){Toast toast=Toast.makeText(MainActivity.this,item.getTitle()+"Selected",Toast.LENGTH_SHORT);//Intent intent2 = new Intent(MainActivity.this,YourSpotActivity.class);//startActivity(intent2);//startActivity(new Intent(MainActivity.this,YourSpotActivity.class));toast.show();return true;}});menu.show();}
当我单击任何一个列表项时,它将启动另一个活动.
我怎么能通过修改上面的代码来做到这一点.请解释一下.
我在菜单中使用了四种车型.当我选择那辆车中的任何一辆时,它将进入特定的活动.
最佳答案
您需要使用如下所示的开关
switch (item.getItemId()) {case R.id.menuitem1:Toast.makeText(getApplicationContext(),"StartActiviy 1",Toast.LENGTH_SHORT).show();// start activity 1return true;case R.id.menuitem2:Toast.makeText(getApplicationContext(),"StartActiviy 2",Toast.LENGTH_SHORT).show();// start activity 2return true;default://default intentreturn true;}
http://developer.android.com/reference/android/widget/PopupMenu.html
