我有从大日志文件中提取的周数列表,它们是使用语法提取的:
- $date --date="Wed Mar 20 10:19:56 2012" +%W;
- 12
我想创建一个简单的bash函数,可以将这些周数转换为日期范围.我想函数应该接受2个参数:$number和$year,例如:
- $week() { ......... }
- $number=12; year=2012
- $week $number $year
- "Mon Mar 19 2012" - "Sun Mar 25 2012"
使用GNU日期:
- $cat weekof.sh
- function weekof()
- {
- local week=$1 year=$2
- local week_num_of_Jan_1 week_day_of_Jan_1
- local first_Mon
- local date_fmt="+%a %b %d %Y"
- local mon sun
- week_num_of_Jan_1=$(date -d $year-01-01 +%W)
- week_day_of_Jan_1=$(date -d $year-01-01 +%u)
- if ((week_num_of_Jan_1)); then
- first_Mon=$year-01-01
- else
- first_Mon=$year-01-$((01 + (7 - week_day_of_Jan_1 + 1) ))
- fi
- mon=$(date -d "$first_Mon +$((week - 1)) week" "$date_fmt")
- sun=$(date -d "$first_Mon +$((week - 1)) week + 6 day" "$date_fmt")
- echo "\"$mon\" - \"$sun\""
- }
- weekof $1 $2
- $bash weekof.sh 12 2012
- "Mon Mar 19 2012" - "Sun Mar 25 2012"
- $bash weekof.sh 1 2018
- "Mon Jan 01 2018" - "Sun Jan 07 2018"
- $