假设我们有这个数据文件.
- john 32 maketing executive
- jack 41 chief technical officer
- jim 27 developer
- dela 33 assistant risk management officer
我想用awk打印
- john maketing executive
- jack chief technical officer
- jim developer
- dela assistant risk management officer
我知道可以使用.
- awk '{printf $1; for(i=3;i<NF;i++){printf " %s",$i} printf "\n"}' < file
问题是它的长,看起来很复杂.
是否还有其他简单的打印方式来打印其余的字段.
将要跳过的字段设置为空白：
- awk '{$2 = ""; print $0;}' < file_name
资料来源：Using awk to print all columns from the nth to the last
