在bash脚本中通过ssh在远程主机上执行命令

我写了一个bash脚本,它应该从文件中读取用户名和IP地址,并通过ssh对它们执行命令.

这是hosts.txt：

user1 192.168.56.232
user2 192.168.56.233

这是myScript.sh：

cmd="ls -l"
 
while read line
do
   set $line
   echo "HOST:" $1@$2
   ssh $1@$2 $cmd
   exitStatus=$?
   echo "Exit Status: " $exitStatus
done < hosts.txt

问题是执行似乎在第一个主机完成后停止.这是输出：

$./myScript.sh
HOST: user1@192.168.56.232
total 2748
drwxr-xr-x 2 user1 user1    4096 2011-11-15 20:01 Desktop
drwxr-xr-x 2 user1 user1    4096 2011-11-10 20:37 Documents
...
drwxr-xr-x 2 user1 user1    4096 2011-11-10 20:37 Videos
Exit Status:  0
$

为什么会这样,我该如何解决？

在您的脚本中,ssh作业获取与读取行相同的标准输入,并且在您的情况下恰好在第一次调用时占用所有行.因此读取线只能看到
输入的第一行.

解决方案：关闭sdin的stdin,或者从/ dev / null更好地重定向. (有些计划
不喜欢stdin关闭)

while read line
do
    ssh server somecommand </dev/null    # Redirect stdin from /dev/null
                                         # for ssh command
                                         # (Does not affect the other commands)
    printf '%s\n' "$line"
done < hosts.txt

如果您不想为/ dev / null重定向循环中的每个作业,您还可以尝试以下方法之一：

while read line
do
  {
    commands...
  } </dev/null                           # Redirect stdin from /dev/null for all
                                         # commands inside the braces
done < hosts.txt
 
 
# In the following,let's not override the original stdin. Open hosts.txt on fd3
# instead
 
while read line <&3   # execute read command with fd0 (stdin) backed up from fd3
do
    commands...       # inside,you still have the original stdin
                      # (maybe the terminal) from outside,which can be practical.
 
done 3< hosts.txt     # make hosts.txt available as fd3 for all commands in the
                      # loop (so fd0 (stdin) will be unaffected)
 
 
# totally safe way: close fd3 for all inner commands at once
 
while read line <&3
do
  {
    commands...
  } 3<&-
done 3< hosts.txt

在bash脚本中通过ssh在远程主机上执行命令

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