- template <class T>
- void max (T &a,T &b)
- {}//generic template #1
- template<> void max(char &c,char &d)
- {} //template specializtion #2
- void max (char &c,char &d)
- {}//ordinary function #3
1,2和3之间有什么区别？
解决方法
>是一个模板函数
>是以前的模板功能的总体专业化(不会超载！)
>是功能的重载
>是以前的模板功能的总体专业化(不会超载！)
>是功能的重载
这是C++ Coding Standards: 101 Rules,Guidelines,and Best Practices摘录：
66) Don’t specialize function templates
Function template specializations never participate in overloading: Therefore,any specializations you write will not affect which template gets used,and this runs counter to what most people would intuitively expect. After all,if you had written a nontemplate function with the identical signature instead of a function template specialization,the nontemplate function would always be selected because it’s always considered to be a better match than a template.
- #include <algorithm>
- template<typename T>
- struct max_implementation
- {
- T& operator() (T& a,T& b)
- {
- return std::max(a,b);
- }
- };
- template<typename T>
- T& max(T& a,T& b)
- {
- return max_implementation<T>()(a,b);
- }
也可以看看：
> Why Not Specialize Function Templates?
> Template Specialization and Overloading
