使用C#如何调整jpeg图像的大小?代码示例会很棒.
解决方法
- public static class ImageHelper
- {
- /// <summary>
- /// Resize the image to the specified width and height.
- /// </summary>
- /// <param name="image">The image to resize.</param>
- /// <param name="width">The width to resize to.</param>
- /// <param name="height">The height to resize to.</param>
- /// <returns>The resized image.</returns>
- public static Bitmap ResizeImage(Image image,int width,int height)
- {
- var destRect = new Rectangle(0,width,height);
- var destImage = new Bitmap(width,height);
- destImage.SetResolution(image.HorizontalResolution,image.VerticalResolution);
- using (var graphics = Graphics.FromImage(destImage))
- {
- graphics.CompositingMode = CompositingMode.SourceCopy;
- graphics.CompositingQuality = CompositingQuality.HighQuality;
- graphics.InterpolationMode = InterpolationMode.HighQualityBicubic;
- graphics.SmoothingMode = SmoothingMode.HighQuality;
- graphics.PixelOffsetMode = PixelOffsetMode.HighQuality;
- using (var wrapMode = new ImageAttributes())
- {
- wrapMode.SetWrapMode(WrapMode.TileFlipXY);
- graphics.DrawImage(image,destRect,image.Width,image.Height,GraphicsUnit.Pixel,wrapMode);
- }
- }
- return destImage;
- }
- public static Bitmap ResizeImage(Image image,decimal percentage)
- {
- int width = (int)Math.Round(image.Width * percentage,MidpointRounding.AwayFromZero);
- int height = (int)Math.Round(image.Height * percentage,MidpointRounding.AwayFromZero);
- return ResizeImage(image,height);
- }
- }
- class Program
- {
- static void Main(string[] args)
- {
- string fileName = @"C:\Images\MyImage.jpg";
- FileInfo info = new FileInfo(fileName);
- using (Image image = Image.FromFile(fileName))
- {
- using(Bitmap resizedImage = ImageHelper.ResizeImage(image,0.25m))
- {
- resizedImage.Save(
- info.DirectoryName + "\\"
- + info.Name.Substring(0,info.Name.LastIndexOf(info.Extension))
- + "_" + resizedImage.Width + "_" + resizedImage.Height
- + info.Extension,ImageFormat.Jpeg);
- }
- }
- }
- }