c# – 使用RestSharp时怎么习惯地处理HTTP错误代码？

我正在使用RestSharp构建一个HTTP API客户端,我注意到,当服务器返回HTTP错误代码(401未经授权,404未找到,内部服务器错误等)时,RestClient.Execute()不会抛出一个异常 – 而是使用一个空的.Data属性获取一个有效的RestResponse.我不想手动检查我的API客户端中的每个可能的HTTP错误代码 – RestSharp是否提供了一种将这些错误传递到我的客户端应用程序的更好方法？

一点点细节. RestSharp公开一个Response.ErrorException属性 – 如果RestClient.Execute< T&()调用引发任何异常,它将通过ErrorException属性公开,而不是抛出.他们的文档包括以下示例：

// TwilioApi.cs
public class TwilioApi {
    const string BaseUrl = "https://api.twilio.com/2008-08-01";
 
    public T Execute<T>(RestRequest request) where T : new()
    {
    var client = new RestClient();
    client.BaseUrl = BaseUrl;
    client.Authenticator = new HttpBasicAuthenticator(_accountSid,_secretKey);
    request.AddParameter("AccountSid",_accountSid,ParameterType.UrlSegment); // used on every request
    var response = client.Execute<T>(request);
 
    if (response.ErrorException != null)
    {
        const string message = "Error retrieving response.  Check inner details for more info.";
        var twilioException = new ApplicationException(message,response.ErrorException);
        throw twilioException;
    }
    return response.Data;
    }
 
}

我在代码中采用了这种模式,但是我的API服务器返回了401 Unauthorized,但是ErrorException属性仍然为空.我可以在RestResponse.StatusCode和RestResponse.StatusDescription属性中看到未经授权的状态代码和错误消息 – 但是我为什么未经授权的响应不会导致ErrorException字段被填充,我感到困惑.

解决方法

尝试为RestSharp WebAPI客户端创建一个通用的错误处理程序时遇到同样的问题.给出这些扩展方法：

public static class RestSharpExtensionMethods
{
    public static bool IsSuccessful(this IRestResponse response)
    {
        return response.StatusCode.IsSuccessStatusCode()
            && response.ResponseStatus == ResponseStatus.Completed;
    }
 
    public static bool IsSuccessStatusCode(this HttpStatusCode responseCode)
    {
        int numericResponse = (int)responseCode;
        return numericResponse >= 200
            && numericResponse <= 399;
    }
}

我提出要求反应是反序列化的：

public async Task<ResponseModel<TResponse>> PerformRequestAsync<TResponse>(IRestRequest request)
{
    var response = await _client.ExecuteTaskAsync<ResponseModel<TResponse>>(request);
    ResponseModel<TResponse> responseData;
 
    if (response.IsSuccessful())
    {
        responseData = response.Data;
    }
    else
    {
        string resultMessage = HandleErrorResponse<TResponse>(request,response);
 
        responseData = new ResponseModel<TResponse>         
        {
            Success = false,ResultMessage = resultMessage
        };
    }
 
    return responseData;
}

但是,在测试期间,我发现当我没有为这种情况配置错误处理时,当请求未映射的URL时,我的Web服务返回HTML格式的404 页面.这导致response.ErrorException属性包含以下字符串：

Reference to undeclared entity ‘nbsp’. Line n,position m.

显然,RestSharp尝试将响应解析为XML,即使内容类型是text / html.也许我会给RestSharp提出一个问题.

当然在生产中,你不应该在打电话给自己的服务时得到404,但是我希望这个客户端是彻底的,可重用的.

所以我可以想到两个解决方案：

>检查状态代码并显示说明
>确保服务返回一个可以解析的错误对象

前者是很容易完成的.在HandleErrorResponse()中,我根据状态代码的数值构建结果消息(用户可呈现)和错误字符串(loggable)：

public string HandleErrorResponse(IRestRequest request,IRestResponse response)
{
    string statusString = string.Format("{0} {1} - {2}",(int)response.StatusCode,response.StatusCode,response.StatusDescription);
    string errorString = "Response status: " + statusString;
 
    string resultMessage = "";
    if (!response.StatusCode.IsScuccessStatusCode())
    {
        if (string.IsNullOrWhiteSpace(resultMessage))
        {
            resultMessage = "An error occurred while processing the request: "
                          + response.StatusDescription;
        }
    }
    if (response.ErrorException != null)
    {
        if (string.IsNullOrWhiteSpace(resultMessage))
        {
            resultMessage = "An exception occurred while processing the request: "
                          + response.ErrorException.Message;
        }
        errorString += ",Exception: " + response.ErrorException;
    }
 
    // (other error handling here)
 
    _logger.ErrorFormat("Error response: {0}",errorString);
 
    return resultMessage;
}

现在,由于我的API响应总是包装在一个ResponseModel< T>我可以使用set up an exception filter and a NotFound route在ResultMessage属性中返回带有错误或异常消息的可解析响应模型：

public class HandleErrorAttribute : ExceptionFilterAttribute
{
    public override void OnException(HttpActionExecutedContext context)
    {
        // (log context.Exception here)
 
        context.Response = context.Request.CreateResponse(HttpStatusCode.InternalServerError,new ResponseModel<object>
        {
            Success = false,ResultMessage = "An exception occurred while processing the request: " + context.Exception.Message
        });
    }
}

和：

public class ErrorController : ApiController
{
    public HttpResponseMessage Handle404()
    {
        const string notFoundString = "The requested resource could not be found";
 
        var responseMessage = Request.CreateResponse(HttpStatusCode.NotFound,ResultMessage = notFoundString
        });
 
        responseMessage.ReasonPhrase = notFoundString;
 
        return responseMessage;
    }
}

这样,我的服务的响应总是可以由RestSharp解析,我可以使用通用日志记录方法：

public string HandleErrorResponse<TResponseModel>(IRestRequest request,IRestResponse<<ResponseModel<TResponseModel>> response)

并记录实际响应//(其他错误处理),如果可用：

if (response.Data != null && !string.IsNullOrWhiteSpace(response.Data.ResultMessage))
{
    resultMessage = response.Data.ResultMessage;
    errorString += string.Format(",Service response: \"{0}\"",response.Data.ResultMessage);
}

c# – 使用RestSharp时怎么习惯地处理HTTP错误代码？

解决方法

猜你在找的C#相关文章