我正在尝试使用UIBezierPath绘制一个指南针并在该线上添加破折号以标记其中的北,南,东,西方向和点.破折号似乎是偏移的(它们没有对齐),特别是在北方和南方方向,而我正在做的方式似乎在路径关闭时添加了额外的破折号.
- let windCircleOrigin = CGPoint(x: self.center.x * 1.3,y: self.bounds.height / 2.0 - 10)
- let windCircleRadius = CGFloat(self.bounds.height * 0.3)
- let windCirclePath: UIBezierPath = UIBezierPath(arcCenter: windCircleOrigin,radius: windCircleRadius,startAngle: 0,endAngle: CGFloat(M_PI) * 2.0,clockwise: true)
- windCirclePath.lineWidth = 6
- let dashes: [CGFloat] = [windCirclePath.lineWidth * 0,windCirclePath.lineWidth * 3 ]
- windCirclePath.setLineDash(dashes,count: dashes.count,phase: 0.0)
- UIColor.whiteColor().setFill()
- UIColor.whiteColor().setStroke()
- windCirclePath.stroke()
- textView(self.windSpeedLabel! + " mph",x: windCircleOrigin.x - 20.0,y: windCircleOrigin.y - 8.0,color: UIColor.whiteColor(),width: 50.0,height: 20.0)
- textView("N",x: windCircleOrigin.x - 7.0,y: windCircleOrigin.y - 70.0,width: 20,height: 20)
- textView("S",y: windCircleOrigin.y + 50.0,height: 20)
- textView("W",x: windCircleOrigin.x - 70.0,height: 20)
- textView("E",x: windCircleOrigin.x + 60.0,height: 20)
- func textView(text: String,x: CGFloat,y: CGFloat,color: UIColor,width: CGFloat,height: CGFloat) {
- let textView = UILabel(frame: CGRectMake(x,y,width,height))
- textView.textAlignment = NSTextAlignment.Left
- textView.textColor = color
- textView.backgroundColor = UIColor.clearColor()
- textView.font = UIFont(name: "HelveticaNeue-Light",size: 12.0)
- textView.text = text
- self.addSubview(textView)
- }@H_301_3@
解决方法
相反,我建议单独绘制每个刻度.然后你可以轻松控制他们的位置.
像这样的东西:
- let path = UIBezierPath()
- let innerRadius: CGFloat = 50
- let outerRadius: CGFloat = 60
- let numTicks = 24
- for i in 0..<numTicks {
- let angle = CGFloat(i) * CGFloat(2*M_PI) / CGFloat(numTicks)
- let inner = CGPoint(x: innerRadius * cos(angle),y: innerRadius * sin(angle))
- let outer = CGPoint(x: outerRadius * cos(angle),y: outerRadius * sin(angle))
- path.moveToPoint(inner)
- path.addLineToPoint(outer)
- }@H_301_3@
然后,您可以使用所需的任何lineWidth(和lineCapStyle)来描述此路径.