我检查并尝试过以前的答案,如何直接从应用程序拨打电话,但我不断收到错误.我刚刚在储物柜中制作了一个按钮,并将其连接到视图控制器.它不断给我“错误审查”,“分隔符,但这并不解决任何事情.我需要向AppDelegate或其他任何内容添加代码吗？我真的想知道在斯威夫特这样做的方式.
- import UIKit
- class ViewController: UIViewController {
- @IBAction func theCallMeButtonMethod(sender: AnyObject) {
- [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"telprompt:0123456789"]]
- }
- override func viewDidLoad() {
- super.viewDidLoad()
- // Do any additional setup after loading the view,typically from a nib.
- }
- override func didReceiveMemoryWarning() {
- super.didReceiveMemoryWarning()
- // Dispose of any resources that can be recreated.
- }
- }
解决方法
此代码将帮助您：
- let phone = "tel://982374234";
- let url:NSURL = NSURL(string:phone);
- UIApplication.sharedApplication().openURL(url);
要么
- var url:NSURL = NSURL(string: "tel://9809088798")
- UIApplication.sharedApplication().openURL(url)
