ios – 将JSON字符串解析为对象数组Objective C.

我有一个从休息Web服务请求返回的 JSON字符串,
我想将这个字符串解析为确定类的对象数组,
这是JSON字符串

[
    {
        "validationCode": null,"FirstName": "Samer","LastName": "Shame","MobileNumber": "0991992993","SimNumber": null,"Email": null,"PhoneNumber": "0991992994","Name": "Abo Alshamat","ID": 1
    },{
        "validationCode": null,"FirstName": "Ahmad","LastName": "Ali","MobileNumber": "0992993994","PhoneNumber": "0992993995","Name": "AL-Kamal","ID": 2
    },"FirstName": null,"LastName": null,"MobileNumber": "0993377800","PhoneNumber": null,"Name": "Abo-MAhmoud","ID": 12
    },"FirstName": "William","LastName": "Ammar","MobileNumber": "0993994995","PhoneNumber": "0993994996","Name": "Four Season","ID": 3
    },"FirstName": "Ammar","LastName": "William","MobileNumber": "0999555777","Name": "uuuuu","ID": 20
    },"MobileNumber": "0999888777","Name": "NewOneFromI2","ID": 18
    },"MobileNumber": "0999998997","PhoneNumber": "0999999998","Name": "JOURY","ID": 4
    },"MobileNumber": "202020","Name": "TestTestRestaurant,Ammar,Hamed","ID": 19
    }
]

我想从中获取实例的类是：

@interface Restaurant : NSObject
@property (nonatomic,strong) NSString *ID;
@property (nonatomic,strong) NSString* FirstName;
@property (nonatomic,strong) NSString* LastName;
@property (nonatomic,strong) NSString* MobileNumber;
@property (nonatomic,strong) NSString* simNumber;
@property (nonatomic,strong) NSString* PhoneNumber;
@property (nonatomic,strong) NSString* Name;
@end

这样做的最佳方式是什么,对不起,问题可能来自基础知识,但我是客观C的新手

感谢您的时间.

解决方法

我建议为您的Restaurant类实现init方法.

-(instancetype) initWithParameters:(NSDictionary*)parameters
{
    self = [super init];
    if (self) {
        //initializations
        _validationCode = parameters[@"validationCode"]; // may be NSNull
        _firstName = [parameters[@"FirstName"] isKindOfClass:[NSNull class]] ? @"" 
                     : parameters[@"FirstName"];
        ...
    }
    return self;
}

注意：你可能有JSON Null的事实,使你的初始化有点复杂.当相应的JSON值为Null时,您需要决定如何初始化属性.

您的参数字典将是您从服务器获得的JSON数组中的第一级字典.

首先,创建一个JSON表示,即JSON中的NSArray对象：

NSError* localError;
id restaurantsObjects = [NSJSONSerialization JSONObjectWithData:data 
                                                        options:0 
                                                          error:&localError];

IFF这没有失败,你的restaurantsObjects现在应该是一个NSArray对象,包含餐厅作为NSDictionarys.

现在,将直接创建一个NSMutableArray,它将填充Restaurant对象：

NSMutableArray* restaurants = [[NSMutableArray alloc] init];
for (NSDictionary* restaurantParameters in restaurantsObjects) {
    Restaurant* restaurant = [Restaurant alloc] initWithParameters: restaurantParameters];
    [restaurants addObject:restaurant];
}

最后,您可以在某个控制器中设置一个属性餐厅：

self.restaurants = [restaurants copy];

ios – 将JSON字符串解析为对象数组Objective C.

解决方法

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