有人有Deserializer工作吗？我在方法“deserialize”而不是元素中获得完整的
JSON表达式？
- public static void main(String[] args) {
- GsonBuilder gb = new GsonBuilder();
- gb.registerTypeAdapter(DummyObject.class,new JsonSerializer<Date>() {
- public JsonElement serialize(Date src,Type typeOfSrc,JsonSerializationContext context) {
- System.out.println("serialize...");
- return new JsonPrimitive(DateUtil.toString(src));
- }
- });
- gb.registerTypeAdapter(DummyObject.class,new JsonDeserializer<Date>() {
- DateFormat format = DateFormat.getInstance();
- public Date deserialize(JsonElement json,Type typeOfT,JsonDeserializationContext context) throws JsonParseException {
- if (!(json instanceof JsonPrimitive)) {
- throw new JsonParseException("The date should be a string value");
- }
- try {
- return format.parse(json.getAsString());
- } catch (ParseException e) {
- throw new JsonParseException(e);
- }
- }
- });
- String jsonExp = "{\"createdDate\":\"2011-12-27T15:21:16\"}";
- Gson g = gb.create();
- DummyObject tf = g.fromJson(jsonExp,DummyObject.class);
- }
解决方法
- Gson gson = new GsonBuilder()
- .setDateFormat("yyyy-MM-dd'T'HH:mm:ssz")
- .create();
