我搜索过这个并且似乎无法找到成功的答案,我正在使用jQuery ajax调用,我无法得到回调的响应.

这是我的coffeescript代码：

initialize: (@blog,@posts) ->
    _url = @blog.url
    _simpleName = _url.substr 7,_url.length
    _avatarURL = exports.tumblrURL + _simpleName + 'avatar/128'
    $.ajax
        url: _avatarURL
        dataType: "jsonp"
        jsonp: "jsonp"
        (data,status) => handleData(data)
handleData: (data) =>
    console.log data
    @avatar = data

这是编译好的JS：

  Blog.prototype.initialize = function(blog,posts) {
    var _avatarURL,_simpleName,_url,_this = this;
    this.blog = blog;
    this.posts = posts;
    _url = this.blog.url;
    _simpleName = _url.substr(7,_url.length);
    _avatarURL = exports.tumblrURL + _simpleName + 'avatar/128';
    return $.ajax({
      url: _avatarURL,dataType: "jsonp",jsonp: "jsonp"
    },function(data,status) {
      return handleData(data);
    });
  };
  Blog.prototype.handleData = function(data) {
    console.log(data);
    return this.avatar = data;
  };

我已经尝试了十几个变种,我无法弄清楚如何写这个？

谢谢.