我正在尝试创建一个循环的进度条(虽然它不再是一个吧,不是吗?).在这个cricle周围有垂直于圆圈的细条.现在的问题是,我的代码不会产生均匀间距的条形.这是代码和结果的图像:
- function MH5PB(canvasId,//the id of the canvas to draw the pb on
- value,//a float value,representing the progress(ex: 0.3444)
- background,//the background color of the pb(ex: "#ffffff")
- circleBackground,//the background color of the bars in the circles
- integerColor,//the color of the outer circle(or the int circle)
- floatColor //the color of the inner circle(or the float circle)
- )
- {
- var canvas = document.getElementById(canvasId);
- var context = canvas.getContext("2d");
- var canvasWidth = canvas.width;
- var canvasHeight = canvas.height;
- var radius = Math.min(canvasWidth,canvasHeight) / 2;
- var numberOfBars = 72;
- var barThickness = 2;
- //margin from the borders,and also the space between the two circles
- var margin = parseInt(radius / 12.5) >= 2 ? parseInt(radius / 12.5) : 2;
- //the thickness of the int circle and the float circle
- var circleThickness = parseInt((radius / 5) * 2);
- //the outer radius of the int circle
- var intOuterRadius = radius - margin;
- //the inner radius of the int circle
- var intInnerRadius = radius - margin - circleThickness;
- //the outer radius of the float circle
- var floatOuterRadius = intOuterRadius - margin - circleThickness;
- //the inner radius of the float circle
- var floatInnerRadius = floatOuterRadius - circleThickness;
- //draw a bar,each degreeStep degrees
- var intCircleDegreeStep = 5;
- // ((2 * Math.PI * intOuterRadius) / (barThickness + 10)) //
- // this area is the total number of required bars //
- // to fill the intCircle.1px space between each bar//
- var floatCircleDegreeStep = 360 / ((2 * Math.PI * floatOuterRadius) / (barThickness + 10));
- context.lineWidth = barThickness;
- context.strokeStyle = circleBackground;
- //draw the bg of the outer circle
- for(i = 90; i < 450; i+=intCircleDegreeStep)
- {
- //since we want to start from top,and move cw,we have to map the degree
- //in the loop
- cxOuter = Math.floor(intOuterRadius * Math.cos(i) + radius);
- cyOuter = Math.floor(intOuterRadius * Math.sin(i) + radius);
- cxInner = Math.floor(intInnerRadius * Math.cos(i) + radius);
- cyInner = Math.floor(intInnerRadius * Math.sin(i) + radius);
- context.moveTo(cxOuter,cyOuter);
- context.lineTo(cxInner,cyInner);
- context.stroke();
- }
- }
编辑:哦,而且行也没有消除锯齿.你知道为什么吗?
我还应该解释一下,这个进度条由两部分组成.外圈(在提供的图像中可见)和内圈.外圆是百分比的整数部分的量(即45在45.98%中的45),内圆是百分比的非整数部分的量(即,在45.98%中为98).因此,您现在知道intCircle和floatCircle是什么:)
解决方法
看来你正在将学位传递给Math.sin和Math.cos.这些函数需要弧度.例如,
- // i degrees to radians.
- Math.sin(i * (Math.PI / 180));