php – 如何在PDO中使用/编写mysql_real_escape

参见英文答案 > real escape string and PDO 3个
在我的代码中我试图将MysqL_real_escape_string转换为PDO语句.有人有关于如何在PDO中编写MysqL_real_escape_string的提示吗？

我在两行中使用MysqL_real_escape_string：
$userName = MysqL_real_escape_string($_ POST [‘username’]);
$password = sha1(MysqL_real_escape_string($_ POST [‘password’]));

PHP
ob_start();
session_start();
include("../database/db.PHP");
$userName = MysqL_real_escape_string($_POST['username']);
$password = sha1(MysqL_real_escape_string($_POST['password']));
echo "MysqL_query($query);
// $rows = $res->fetch(PDO::FETCH_ASSOC); 
$rows = MysqL_fetch_assoc($res);
echo "MysqL_num_rows($res) . "PHP");
// }
// else
// {
//  echo 'Username and password dont match 
PHP?loginerror=yes");
// } 
if(MysqL_num_rows($res)>0)
{
    $_SESSION['userName']  =  $rows['admin_usr_name'];
    $_SESSION['admin_id'] = $rows['admin_id'];
    header("location: ../pages/content.PHP");
}
else
{
    echo 'Username and password dont match 
PHP?loginerror=yes");
}

？>

这就是我试图用PDO做的事情

  $host = "localhost"; 
$user = "root"; 
$password = "root";
$db = "blog";
$dsn = "MysqL:host=$host;dbname=$db;charset=utf8";
$opt = array(PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,PDO::ATTR_DEFAULT_FETCH_MODE => PDO::FETCH_ASSOC);
$pdo = new PDO($dsn,$user,$password,$opt);
$username = $_POST['username'];
$password = $_POST['password'];
$query = "select * from tbladmin where admin_usr_name=:userName and admin_pwd=:passWord";
try 
{   
$databas = new PDO($dsn,$password);
} 
catch (PDOException $e) 
{
echo 'Connection Failed: ' . $e->getMessage();
}
$statement = $databas->prepare($query);
$statement->execute(array(':userName'=>$username,':passWord'=> $password)); 
$row = $statement->fetch();

我总是得到这个错误：
在非对象上调用成员函数prepare()

最佳答案

关键是通过使用带参数化查询和绑定值的预准备语句,您不需要诸如MysqL_real_escape_string之类的东西.

查看PDO documentation有关如何使用绑定值和参数化查询/预准备语句的信息.

关键是你要编写一个SQL查询：

$query = $pdo->prepare("SELECT * FROM users WHERE username = ? and password = ?");

然后你会传入绑定值代替？符号,因此查询只是按字面意思运行：

$query->bindParam(1,$username);
$query->bindParam(2,$password);

任何类型的sql注入尝试,例如1′; DROP用户 – 在上面的变量中将不再起作用,因为它将按字面意思调用.

php – 如何在PDO中使用/编写mysql_real_escape_string？

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