起因:源端数据库应用程序逻辑错误,导致重大量重试回滚,日产生归档300GB,异地备份在10Mbps的网速下,产生了archive gap;
解决流程:
1 查出备库当前的scn号
- select current_scn from v$database;
- 1612480746
2 在主库生成基于备库scn的增量备份
- --primary
- show all;
- run{
- ALLOCATE CHANNEL d1 TYPE disk;
- set limit channel d1 kbytes=104857600;
- BACKUP INCREMENTAL FROM SCN 1612480746 DATABASE FORMAT 'J:\%U_for_stb.bk' include current controlfile for standby;
- }
3 传送日志到备库
- --standby
- catalog start with 'e:\inc';
4 应用control file,增量备份集
- restore standby controlfile to 'e:\control01.ctl' ;
- shutdown immediate;
- copy e:\control01.ctl E:\ORADATA\TCIS\CONTROL01.CTL
- copy e:\control01.ctl E:\ORADATA\TCIS\CONTROL02.CTL
- copy e:\control01.ctl E:\ORADATA\TCIS\CONTROL03.CTL
recover database noredo;
报错:
- RMAN-03002: recover 命令 (在 07/08/2018 10:49:09 上) 失败
- RMAN-06094: 数据文件5必须重新存储
启动原先的备库,select name from v$datafile
发现文件有重新rename的;有点梗;
5 修改数据文件位置
- alter system set standby_file_management=manual;
- alter database rename file 'E:\ORADATA\TCIS\UBSS_INDX01.DBF' to 'd:\oradata\tcis\ubss_indx01.dbf';
- alter database rename file 'E:\ORADATA\TCIS\UBSS_INDX02.DBF' to 'd:\oradata\tcis\ubss_indx02.dbf';
6 再次recover database noredo
以老的控制文件启动,发现第16号文件是之后添加的
7 主库上备份16号文件backup datafile 16 format 'j:\16.bak';
8 备库上恢复16文件
- --primary
- catalog start with 'e:\inc';
- restore datafile 16 ;
- recover database noredo;
9 清理无效的备份片,再次重复2之后的步骤,backup,restore controlfile,rename datafile,recover database ;
10 恢复完成后检查
复原参数alter system set standby_file_management=auto;
启动recoveralter database recover managed standby database disconnect;
检查日志应用情况
- sql> select status,blocks,process,sequence# from v$managed_standby;
- STATUS BLOCKS PROCESS SEQUENCE#
- ------------ ---------- --------- ----------
- CONNECTED 0 ARCH 0
- CONNECTED 0 ARCH 0
- CONNECTED 0 ARCH 0
- CONNECTED 0 ARCH 0
- IDLE 20480 RFS 45261
- IDLE 20480 RFS 45262
- IDLE 0 RFS 0
- APPLYING_LOG 81560 MRP0 45248
检查归档,删除已应用的归档
- select a.thread#,a.sequence#,a.applied,a.name
- from v$archived_log a,v$database d
- where a.activation# = d.activation#
- and a.applied='YES' order by 2;