我正在尝试将数据库中的所有错误记录到表中.因此,当用户sys i编写以下代码时:
华金
@H_404_13@
不要查询v $sql;使用ora_sql_txt获取语句.
CREATE TABLE servererror_log ( error_datetime TIMESTAMP,error_user VARCHAR2(30),db_name VARCHAR2(9),error_stack VARCHAR2(2000),captured_sql VARCHAR2(1000)); / CREATE OR REPLACE TRIGGER log_server_errors AFTER SERVERERROR ON DATABASE DECLARE captured_sql VARCHAR2(1000); BEGIN SELECT q.sql_text INTO captured_sql FROM gv$sql q,gv$sql_cursor c,gv$session s WHERE s.audsid = audsid AND s.prev_sql_addr = q.address AND q.address = c.parent_handle; INSERT INTO servererror_log (error_datetime,error_user,db_name,error_stack,captured_sql) VALUES (systimestamp,sys.login_user,sys.database_name,dbms_utility.format_error_stack,captured_sql); END log_server_errors;@H_502_3@但是,当我强制尝试从不存在的表中选择一个错误时,它不会在表中记录错误. @H_502_3@有没有办法检查触发器是否会触发?此外,我尝试创建一个测试表来插入那里,但它也不起作用,即使将触发器定义为自治事务并在触发器内提交. @H_502_3@谢谢,
华金
CREATE OR REPLACE TRIGGER log_server_errors AFTER SERVERERROR ON DATABASE DECLARE sql_text ora_name_list_t; stmt clob; n number; BEGIN n := ora_sql_txt(sql_text); if n > 1000 then n:= 1000; end if ; FOR i IN 1..n LOOP stmt := stmt || sql_text(i); END LOOP; INSERT INTO servererror_log (error_datetime,captured_sql) VALUES (systimestamp,stmt); commit; END log_server_errors; /@H_502_3@然后:
sql> select * from c;@H_502_3@这会产生:
select * from c * ERROR at line 1: ORA-00942: table or view does not exist@H_502_3@现在可以查询:
select * from servererror_log;@H_502_3@生产:
ERROR_DATETIME --------------------------------------------------------------------------- ERROR_USER DB_NAME ------------------------------ --------- ERROR_STACK -------------------------------------------------------------------------------- CAPTURED_sql -------------------------------------------------------------------------------- 11-FEB-09 02.55.35.591259 PM SYS TS.WORLD ORA-00942: table or view does not exist select * from c