以下是我在yii2 / advanced / backend的默认LoginForm模型中尝试过的,但不幸的是isNumeric验证器根本没有启动：

public function rules()
{
    return [
        // username and password are both required
        [['username','password'],'required'],// username should be numeric
        ['username','isNumeric'],'string','length'=>8],// password is validated by validatePassword()
        ['password','validatePassword'],];
}

/**
 * Validates if the username is numeric.
 * This method serves as the inline validation for username.
 *
 * @param string $attribute the attribute currently being validated
 * @param array $params the additional name-value pairs given in the rule
 */
public function isNumeric($attribute,$params)
{
    if (!is_numeric($this->username))
        $this->addError($attribute,Yii::t('app','{attribute} must be numeric',['{attribute}'=>$attribute]));
}

/**
 * Validates the password.
 * This method serves as the inline validation for password.
 *
 * @param string $attribute the attribute currently being validated
 * @param array $params the additional name-value pairs given in the rule
 */
public function validatePassword($attribute,$params)
{
    if (!$this->hasErrors()) {
        $user = $this->getUser();
        if (!$user || !$user->validatePassword($this->password)) {
            $this->addError($attribute,'Incorrect username or password.');
        }
    }
}

我还尝试添加一个相关帖子(https://stackoverflow.com/a/27817221/2037924)中建议的场景,但只有在场景中没有包含密码字段时才会起作用(如显示错误).

这是实现这一目标的好方法,还是你能想到一个更好的方法吗？

注意：我将用户名定义为字符串的原因是因为数字可能包含前导0.