String str5 = "8OABCE[34][AA]";
        Pattern pattern = Pattern.compile("(\\[\\d+\\])(\\[[0-9a-zA-Z]+\\])$");
        Matcher matcher = pattern.matcher(str5);
        while (matcher.find()) {
            //输出正则表达式过滤出来的内容
            //matcher.group(0) 全字符串
            //matcher.group(1)第一个括号里面的内容
            //matcher.group(2)第二个括号里面的内容
            System.out.println("----------" + matcher.group(1));
            String str9 = matcher.group(1);
            String str10 = str5.replace(str9,"");
            System.out.println("----------" + str10);
        }
        
        String ss ="ooaaooo";
        Pattern pattern1 = Pattern.compile("(o+)");
        Matcher mt = pattern1.matcher(ss);
        //用while可以找到所有相匹配的，并输出
        while(mt.find()){
            System.out.println(mt.group(1) + "|||" + mt.start());
        }
        //用if只能找到第一个相匹配，并输出
        if(mt.find()){
            System.out.println(mt.group(1) + "|||" + mt.start());
        }