解决方法
必填答案
scala> val l = List("abc","abc","cbe","cab")
l: List[String] = List(abc,abc,cbe,cab)
scala> l.groupBy(identity).mapValues(_.size)
res91: scala.collection.immutable.Map[String,Int] = Map(cab -> 1,abc -> 2,cbe -> 1)
@H_404_22@
