- class OAuthToken: NSObject,NSCoding {
- var refreshToken: String?
- var accessToken: String?
- var scope: String?
- convenience init?(refreshToken: String?,accessToken: String?,scope:String) {
- self.init()
- if let acutalRefreshToken = refreshToken as String? {
- self.refreshToken = acutalRefreshToken
- } else {
- return nil
- }
- if let actualAccessToken = accessToken as String? {
- self.accessToken = actualAccessToken
- }else {
- return nil
- }
- self.scope = scope
- }
- convenience init?(attributes: Dictionary<String,AnyObject>,scope: String) {
- var aRefreshToken: String!
- var anAccessToken: String?
- aRefreshToken = attributes["refresh_token"] as String?
- anAccessToken = attributes["access_token"] as String?
- let token = self.init(refreshToken: aRefreshToken,accessToken: anAccessToken,scope: scope) as OAuthToken // () is not convertible to OAuthToken
- if token != nil {
- storeInKeyChain()
- } else {
- return nil
- }
- }
- }
当你在另一个内部调用嵌套的可用初始化程序时,如何检查nil的可用初始化程序?
let token = self.init(refreshToken:aRefreshToken,accessToken:anAccessToken,scope:scope)想要返回一个type()对象,而不是可转换为我的类.我如何使用此模式并仅将对象存储到钥匙串(如果它实际上已成功创建)?
我认为当你调用一个超类的可用初始化器时,如果它失败则会有一个隐式返回.
事实上,关于Failable Initializers的文档指出:
If the superclass initialization fails because of an empty name value,the entire initialization process fails immediately and no further initialization code is executed