@H_404_2@
在编程时我是新手,刚开始学习
Swift.对于我正在努力解决的以下阵列概念,我们将不胜感激.
如何缩短以下编码,以便减少If语句的数量.因此,当选择“battlename = name [0]”索引时,语句会自动选择相同索引级别的相应怪物,而不必使用如此多的If语句.
希望我有意义.
var names = ["Lancelot","Arthur","Gawain","Galahad"]
var monsters = ["Dragon","Boar","Giant","Griffin"]
let battlename = names[1]
print(battlename,"Vs.",monsters)
if battlename == names[0] {
print(battlename,monsters[0])
}
else if battlename == names[1] {
print(battlename,monsters[1])
}
else if battlename == names[2] {
print(battlename,monsters[2])
}
else if battlename == names[3] {
print(battlename,monsters[3])
}
解决方法
您可以使用以下单个条件替换所有条件：
if let index = names.indexOf(battlename) {
print(battlename,monsters[index])
}
此外,如果您想要在简介中打印怪物名称列表,而不是仅打印数组,您可以将项目作为字符串加入：
print(battlename,monsters.joinWithSeparator(",")) // "Arthur Vs. Dragon,Boar,Giant,Griffin"
@H_404_2@
