我有以下,无论我尝试什么命令窗口再次打开和关闭.没有显示图表,也没有写入文件.任何有c使用gnuplot的解决方案的人.我有4.4和4.6rc1可用.
- #ifdef WIN32
- gp = _popen("C:\Program Files (x86)\gnuplot\bin\pgnuplot.exe","w");
- #else
- gp = popen("gnuplot -persist","w");
- #endif
- if (gp == NULL)
- return -1;
- /* fprintf(gp,"unset border\n");
- fprintf(gp,"set clip\n");
- fprintf(gp,"set polar\n");
- fprintf(gp,"set xtics axis nomirror\n");
- fprintf(gp,"set ytics axis nomirror\n");
- fprintf(gp,"unset rtics\n");
- fprintf(gp,"set samples 160\n");
- fprintf(gp,"set zeroaxis");
- fprintf(gp," set trange [0:2*pi]");*/
- fprintf(gp,"set term png\n");
- fprintf(gp,"set output \"c:\\printme.png\"");
- fprintf(gp,"plot .5,1,1.5\n");
- fprintf(gp,"pause -1\n");
- fflush(gp);
以下程序已在Windows上使用Visual Studio和MinGW编译器以及使用gcc的GNU / Linux进行了测试. gnuplot二进制文件必须位于路径上,而在Windows上,必须使用二进制文件的管道pgnuplot版本.
我发现Windows管道比GNU / Linux上的相应管道慢得多.对于大型数据集,在Windows上通过管道将数据传输到gnuplot很慢并且通常不可靠.此外,按键等待代码在GNU / Linux上更有用,其中一旦调用pclose(),绘图窗口将关闭.
- #include <iostream>
- #include <stdio.h>
- #include <stdlib.h>
- // Tested on:
- // 1. Visual Studio 2012 on Windows
- // 2. Mingw gcc 4.7.1 on Windows
- // 3. gcc 4.6.3 on GNU/Linux
- // Note that gnuplot binary must be on the path
- // and on Windows we need to use the piped version of gnuplot
- #ifdef WIN32
- #define GNUPLOT_NAME "pgnuplot -persist"
- #else
- #define GNUPLOT_NAME "gnuplot"
- #endif
- int main()
- {
- #ifdef WIN32
- FILE *pipe = _popen(GNUPLOT_NAME,"w");
- #else
- FILE *pipe = popen(GNUPLOT_NAME,"w");
- #endif
- if (pipe != NULL)
- {
- fprintf(pipe,"set term wx\n"); // set the terminal
- fprintf(pipe,"plot '-' with lines\n"); // plot type
- for(int i = 0; i < 10; i++) // loop over the data [0,...,9]
- fprintf(pipe,"%d\n",i); // data terminated with \n
- fprintf(pipe,"%s\n","e"); // termination character
- fflush(pipe); // flush the pipe
- // wait for key press
- std::cin.clear();
- std::cin.ignore(std::cin.rdbuf()->in_avail());
- std::cin.get();
- #ifdef WIN32
- _pclose(pipe);
- #else
- pclose(pipe);
- #endif
- }
- else
- std::cout << "Could not open pipe" << std::endl;
- return 0;
- }
