有人可以帮助我使用此代码吗？我正在使用Python 3，这是初级课程。
加拿大统计局根据以下假设预测人口：
我的任务：
到目前为止，我只能弄清楚的是：
mylist= [1,2,3,4,5,6,7,8,9,10]
for x in mylist:
print("Year",x,"has a population of",r)
def population(b,d,i):
p=(b+i-d)
return p
a=(1/78)
b=(1/105)
c=(1/147)
r=population (a,b,c)
答案1：
import math
current_population=38233484
seconds_per_day=3600*24
days_per_year=365
seconds_per_birth=78
seconds_per_death=105
seconds_per_inmigrant=147
births_per_year=math.trunc(days_per_year*seconds_per_day/seconds_per_birth)
deaths_per_year=math.trunc(days_per_year*seconds_per_day/seconds_per_death)
inmigrants_per_year=math.trunc(days_per_year*seconds_per_day/seconds_per_inmigrant)
for years in range(10):
new_population=current_population+(births_per_year+inmigrants_per_year-deaths_per_year)*(years+1)
print("Year",years+1,"has a population of",new_population)
答案2：
import math
def input_years():
user_input=input("Enter a positive number of years: ")
return int(user_input)
current_population=38233484
seconds_per_day=3600*24
days_per_year=365
seconds_per_birth=78
seconds_per_death=105
seconds_per_inmigrant=147
births_per_year=math.trunc(days_per_year*seconds_per_day/seconds_per_birth)
deaths_per_year=math.trunc(days_per_year*seconds_per_day/seconds_per_death)
inmigrants_per_year=math.trunc(days_per_year*seconds_per_day/seconds_per_inmigrant)
years=input_years()
if years <0:
print("Sorry,number of years must be positive")
else:
new_population=current_population+(births_per_year+inmigrants_per_year-deaths_per_year)*(years)
print("After",years,"years new population is",new_population)
运行一个云功能，假设它每78秒运行一次，每105秒运行一次，而每147秒运行一次，这将分别增加/减少总人口数。
PHP /拉威尔与firebase相同，但具有 CronJob 。
蟒蛇这有点棘手，因为使用python确实很难设置云函数，因此您将不得不处理python云函数，或者在客户端提取填充计数并运行一个会递增/递减的间隔人口计数。
使用具有云功能的Firebase。