我有一个并行构建的多个项目,每个项目在某个时间点确实调用<Exec />
任务。该执行任务正在运行3pty工具,如果该工具的另一个实例正在运行,则该工具将崩溃。是否有一些本机方式如何在msbuild中实现“互斥体”?
(可行的)明显的解决方案是使构建同步-但这会减慢整个构建的速度。
我有一个并行构建的多个项目,每个项目在某个时间点确实调用<Exec />
任务。该执行任务正在运行3pty工具,如果该工具的另一个实例正在运行,则该工具将崩溃。是否有一些本机方式如何在msbuild中实现“互斥体”?
(可行的)明显的解决方案是使构建同步-但这会减慢整个构建的速度。
最后我编写了自己的 msbuild 扩展库,如下所示
msbuild 部分:
<UsingTask TaskName="MutexExec" AssemblyFile="$(CommonTasksAssembly)" />
C# 部分:
// <PackageReference Include="Microsoft.Build.Utilities.Core" Version="16.9.0" />
// <PackageReference Include="Microsoft.Build.Tasks.Core" Version="16.9.0" />
// <PackageReference Include="Microsoft.Build.Framework" Version="16.9.0" />
using System;
using System.Diagnostics;
using System.Threading;
using Microsoft.Build.Framework;
using Microsoft.Build.Tasks;
/// <summary>
/// Like a Exec task,but with critical section
/// </summary>
public class MutexExec : Exec
{
/// <summary>
/// Gets or sets mutex name
/// </summary>
[Required]
public string MutexName { get; set; }
/// <inheritdoc />
public override bool Execute()
{
var timeout = TimeSpan.FromMinutes(5);
var stopwatch = Stopwatch.StartNew();
while (stopwatch.Elapsed < timeout)
{
bool createdNew;
using (var mutex = new Mutex(true,this.MutexName,out createdNew))
{
if (createdNew)
{
bool result = base.Execute();
try
{
this.Log.LogMessage(MessageImportance.Normal,"Releasing {0}",this.MutexName);
mutex.ReleaseMutex();
}
catch (Exception e)
{
this.Log.LogError("Failure releasing {0} - {1}",e);
}
return result;
}
}
this.Log.LogMessage(MessageImportance.Normal,"Waiting for {0} - ellapsed {1}",stopwatch.Elapsed);
Thread.Sleep(5000);
continue;
}
this.Log.LogError("Failed to acquire {0} in {1}.",timeout);
return false;
}
}