您好，我编写了这段代码，目的是查看天气是否为palyndrom，执行时出现段错误，您能帮上忙吗？这是查看单词是否为palyndrom的好方法吗？ 提前谢谢

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int m=1;

void palindromi();

int main (int argc,char *argv[]) {

    int len,a,i=0;

    if (argc != 2)
        exit(0);

    len = strlen(argv[1]);
    a = len-1;
    printf("La lunghezza della parola e' %d\n",len);

    palindromi(argv[1],len,i);

    return 0;
}

void palindromi(char *parola,int len,int a,int i) {

    if (i < len/2){
        if (parola[i] == parola[a]) {
            palindromi(parola,a--,i++);
        }
        else
            m = 0;
    }

    if (m == 1)
        printf("La parola e' palindroma\n");
    if (m == 0)
        printf("La parola non e' palindroma\n");
}