我想使此代码正常工作
data.append(data2[['Away','Home']],ignore_index=True,sort=False)\
.replace(np.nan,'')
我创建了一个带有数据数组的类来保存项目。和steps数组来保存操作。然后我使用了可链接的诺言来执行它们。那是做我想要达到的最好的方法吗？我真的需要将操作存储在数组中吗？
$('start') // push initial value to an array
.addItem(2) // add another value
.printAll() // print everything in array
.delay(2000) // wait x seconds
.addItem(5)
.printAll()
.start(); // execute all the commands before this line
尽管根据我的说法，您的问题属于https://codereview.stackexchange.com/，但我尝试着考虑另一种没有承诺的实现。它仅适用于闭包和回调：
class Sync {
constructor() {}
init(startValue) {
this.data = [startValue];
this.steps = [];
return this;
}
addItem(value) {
const append = v => this.data.push(v);
this._addStep(append,value);
return this;
}
printAll() {
this._addStep(v => console.log(v.join()),this.data);
return this;
}
delay(value) {
this._addStep(window.setTimeout,value);
return this;
}
_addStep(fun,...args) {
this.steps.push({
fun,args
});
}
start() {
let finalFunction;
this.steps.reverse().forEach(({ fun,args }) => {
if (fun === window.setTimeout) {
finalFunction = finalFunction ? encloseFunctionWithArgs(null,null,finalFunction,next => setTimeout(next,...args)) : null;
} else {
finalFunction = encloseFunctionWithArgs(fun,args,finalFunction);
}
});
finalFunction();
return this;
}
}
function encloseFunctionWithArgs(fun,next,trigger) {
return function () {
if (fun)
fun(args);
if (next)
trigger ? trigger(next) : next();
}
}
const lib = new Sync();
const $ = lib.init.bind(lib);
$('start')
.addItem(2)
.printAll()
.delay(2000)
.addItem(5)
.printAll()
.start();
编辑
我终于设法实现了您想要的：
class Sync {
constructor() {}
init(startValue) {
this.promise = new Promise(resolve => this.start = resolve).then(() => [startValue]);
return this;
}
addItem(value) {
this.promise = this.promise.then(v => {
v.push(value);
return v;
});
return this;
}
printAll() {
this.promise = this.promise.then(v => {
console.log(v.join());
return v;
});
return this;
}
delay(value) {
this.promise = this.promise.then(v => new Promise(resolve => setTimeout(() => resolve(v),value)));
return this;
}
}
const lib = new Sync();
const $ = lib.init.bind(lib);
$('start')
.addItem(2)
.printAll()
.delay(2000)
.addItem(5)
.printAll()
.start();