没有执行程序的Java可调用异步程序

我环顾四周,有很多例子,但找不到直接的答案。请参见下面的代码。我不想将我的可调用任务提交给执行者以取得未来。我只是想称其为原始。所以我直接调用.call()会阻塞当前线程吗?我的意思是会阻止通话吗?谢谢

public class CustomCallable implements Callable<Long> {
private long number;

public CustomCallable(final long number) {
    this.number = number;
}

@Override
public Long call() throws Exception {
     //do something    
    return number;
  }
}


public static void main(String[] args) {

    for (int i = 0; i < 10; i++) {
        Callable<Long> cCallable = new CustomCallable(i);
            cCallable.call();//The question is: is this going to block until it finishes the current call,or continue spinning others. Is the loop going to continue without waiting the previous call? or just continue until it reaches <10? 
    }
}
aazhenzhen 回答:没有执行程序的Java可调用异步程序

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