我正在做一个作业，该作业要求读取文件并返回字母的频率。目前，我以return语句作为显示方法，以便文件中的字母显示在表格中，而这些字母的计数器在下一行。这是我的问题：我将显示方法嵌套在for循环中，该循环嵌套在while循环中，并且在读取文件后当前不返回任何内容。 while循环的构造使其仅在读取文件时才运行（文件的末尾为-1）。 for循环应该检查一下我的inputvalue的索引值是否与字母的索引值相同（如果是，则显示）。正如我已经提到的，它目前不显示任何内容。尽管进行了研究（并问了同学），但我仍然无法弄清问题所在。可以给出的任何见解将不胜感激。

 final static int AlphabetSize = 26;
    final static Scanner cin = new Scanner(System.in);
    final static int MaxBarLength = 50;

    public static void main(String[] args) {
        String fileName;

        // sign-on
        out.print("CPS 150 Assignment 6 by Anthony Lapham  \n\n");

        // get the file name
        out.print("Enter the file name: ");
        fileName = cin.nextLine();

        // process the file
        try {
            processFile(fileName);
        } catch (FileNotFoundException e) {
            out.println(fileName + " was not found,program terminated");
        } catch (IOException e) {
            out.println("Unforeseen IO exception,stack trace follows");
            e.printStackTrace();
        } // end try

        // sign-off
        out.print("\nAssignment 6 complete\n\n");
    } // end main

    static void processFile(final String fileName)
            throws FileNotFoundException,IOException {
        FileInputStream inFile = new FileInputStream(fileName);
        int inputvalue = 0; // character read as an integer
        char ch;            // variable to hold input value typecast to char
        int[] counters = new int[AlphabetSize];
        final char[] alphabet = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};

        // declare other variables you need
        int i;

        // implement a standard sentinel control loop here
        int SENTINEL = -1;
        // read first input character as an integer
        inputvalue = inFile.read();

        while (inputvalue != SENTINEL) {
            ch = (char) inputvalue;
            for(i = 0; i < counters.length; i++){
                if(char2int(ch) == alphabet[i]){
               display(alphabet,counters);
           }
            }




            // add code to process this character
            // read next input character
            inputvalue = inFile.read();
        } // end loop

        inFile.close();

        // generate appropriate output
    } // end function

    static void display(final char[] alphabet,final int[] counters) {
        // write code for this function
        int counter = 0;
        int charCounter;
        int num;
        out.print("The file has " + alphabet + " alphabetic,and " + counters + " other characters.\n\n");
        out.println("Letter   Count    Bar");
        out.println("------   -----    ---");
//        while (counter < AlphabetSize) {
////            out.printf("%5s %-4s %-3s",alphabet,counters,printChars(counters,alphabet));
//            counter++;
//        }

    } // end function

    // char2int is complete
    static int char2int(final char arg) {
        if (!Character.isLetter(arg)) {
            return -1;
        } else {
            return (int) Character.toUpperCase(arg) - (int) 'A';
        }
    } // end function

    // function printChars writes n copies of the character c to the
    // standard output device
    static void printChars(final int n,final char c) {
        // write the code
        for (int i = 0; i < n; i++) {
            if (i == char2int(c)) {
                out.print("*");
            }
        }

    } // end printChars

    // this function returns the largest value stored in the array
    static int maxCount(final int[] arr) {
        // write the code
        return 0;
    } // end function

}