您可以split()上的字符串"AND"，然后在列表中的各项之间插入"AND。似乎您也不需要任何尾随空格，因此也需要strip()。

string = "events.error > 5 AND timeseries.temperature < 20 AND variants.battery = 'Li' AND vehicle.name = 'Audi'"

def intersperse(lst,item):
    result = [item] * (len(lst) * 2 - 1)
    result[0::2] = lst
    return result

result = intersperse([x.strip() for x in string.split("AND")],"AND")

print(result)

输出：

['events.error > 5','AND','timeseries.temperature < 20',"variants.battery = 'Li'","vehicle.name = 'Audi'"]

最简单的方法是使用re.split，将分隔符放在一组中将使其保留在输出中：

import re

string = "events.error > 5 AND timeseries.temperature < 20 AND variants.battery = 'Li' AND vehicle.name = 'Audi'"

re.split(r'(AND)',string)

输出：

['events.error > 5 ',' timeseries.temperature < 20 '," variants.battery = 'Li' "," vehicle.name = 'Audi'"]

编辑：当您包含第二个分隔符“或”时，更新版本：

import re

string = "events.error > 5 AND timeseries.temperature < 20 OR variants.battery = 'Li' AND vehicle.name = 'Audi'"

re.split(r'(AND|OR)','OR'," vehicle.name = 'Audi'"]

如果要消除字符串周围的空格，可以在分隔符中但在组之外包含任意数量的前导和尾随空格，这样它们就不会出现在输出中：

import re

string = "events.error > 5 AND timeseries.temperature < 20 OR variants.battery = 'Li' AND vehicle.name = 'Audi'"

re.split(r'\s*(AND|OR)\s*',string)  # include the spaces in the separator,# but don't keep them 

输出：

['events.error > 5',"vehicle.name = 'Audi'"]

您可以先用string.split("AND")分割字符串，再用.strip()分割字符串，以丢失前导/尾随空格：

my_string = "events.error > 5 AND timeseries.temperature < 20 AND variants.battery = 'Li' AND vehicle.name = 'Audi'" 
my_list = my_string.split('AND') 
my_list = [x.strip() for x in my_list]
print(my_list)

返回

['events.error > 5',"vehicle.name = 'Audi'"]

请注意，如果没有.strip()，则会保留不必要的空白，而这可能是您不希望的。

您可以将split()与itertools.cycle()和zip()组合：

import itertools


string = "events.error > 5 AND timeseries.temperature < 20 AND variants.battery = 'Li' AND vehicle.name = 'Audi'"
print([x for y in zip(string.split(' AND '),itertools.cycle(['AND'])) for x in y][:-1])
# ['events.error > 5',"vehicle.name = 'Audi'"]