返回最新日期为sql max(DATE)的文章

我有以下查询:

 SELECT  MAX(b.upd_dtime) as MaxT,b.vo_no as vo_no,y.item_no
 FROM vo_order_t b JOIN (
     SELECT a.vo_no,a.item_no FROM vo_item_t a where a.item_no IN('00265929')) y ON y.vo_no = b.vo_no
 GROUP BY b.vo_no,y.item_no

此查询的输出如下:

Date                Vo_No   Item_No
2019-05-27 08:37:07 0242625 00265929
2019-05-27 07:52:29 0282971 00265929
2019-05-27 07:52:29 0282972 00265929
2019-05-27 07:52:29 0696864 00265929
2018-02-13 22:57:09 0282984 00265929
2019-05-27 07:52:29 0395347 00265929
2019-05-27 07:52:29 0242712 00265929
2019-05-27 07:52:29 0242624 00265929
2019-05-27 07:52:29 0441449 00265929
2019-05-27 07:52:29 0400026 00265929

但是我希望输出如下:

Date                Vo_no   Item_No
2019-05-27 08:37:07 0242625 00265929

如何修改我的查询来实现?

yykingmax 回答:返回最新日期为sql max(DATE)的文章

您可以使用聚合的keep子句返回由另一个排序的第一个/最后一个值:

create table t (
  c1 date,c2 varchar2(10),c3 varchar2(10)
);
alter session set nls_date_format = 'YYYY-MM-DD HH24:MI:SS';

insert into t values ( '2019-05-27 08:37:07','0242625','00265929' );
insert into t values ( '2019-05-27 07:52:29','0282971','0282972','0696864','00265929' );
insert into t values ( '2018-02-13 22:57:09','0282984','0395347','0242712','0242624','0441449','0400026','00265929' );

select max ( c1 ) c1,max ( c2 ) keep (
         dense_rank first
         order by c1 desc
       ) c2,c3
from   t
group  by c3;

C1                    C2        C3         
2019-05-27 08:37:07   0242625   00265929   
,

分析功能可能会有所帮助。您需要的代码从第6行开始。

SQL> with test (upd_dtime,vo_no,item_no) as
  2    (select 20190527,242625,265929 from dual union all
  3     select 20190213,282984,265929 from dual union all
  4     select 20190118,400026,265929 from dual
  5    )
  6  select upd_dtime,item_no
  7  from (
  8         select upd_dtime,item_no,9           row_number() over (partition by item_no order by upd_dtime desc) rn
 10         from test
 11       )
 12  where rn = 1;

 UPD_DTIME      VO_NO    ITEM_NO
---------- ---------- ----------
  20190527     242625     265929

SQL>

[编辑:已应用于您的表]

由于您无法将上述代码调整为实际表(下一次,发布包含CREATE TABLE和INSERT INTO示例数据的测试用例将是一个好主意),如下所示:>

  • yourq CTE代表您发布的查询。我不知道您为什么使用嵌入式视图(其别名为y);为什么不像我一样简单地加入vo_order_tvo_item_t
  • 其余与我之前发布的完全相同

因此:复制/粘贴此代码,然后在您的模式中执行它。如果我没有打错字,那应该没问题。如我所说,如果没有的话,请发布测试用例。

with 
yourq as
-- your query,rewritten
  (select b.upd_dtime,b.vo_no,a.item_no
   from vo_order_t b join vo_item_t a on a.vo_no = b.vo_no
   where a.item_no = '00265929'
  )
select upd_dtime,item_no
from (
      select upd_dtime,row_number() over (partition by item_no order by upd_dtime desc) rn
      from yourq
     )
where rn = 1; 
,

您可以使用MAX() OVER (PARTITION BY ...)分析函数:

WITH t AS
(   
 SELECT MAX(v.upd_dtime) OVER (PARTITION BY v.item_no) AS MaxT,v.vo_no AS vo_no,v.item_no,v.upd_dtime 
   FROM vo_order_t v
  WHERE v.item_no = '00265929'
)
SELECT *
  FROM t
 WHERE upd_dtime = MaxT   

如果您使用的是12c +版本,请直接使用FETCH FIRST 1 ROW ONLY来获取最新文章:

 SELECT MAX(v.upd_dtime) OVER (PARTITION BY v.item_no) AS MaxT,v.upd_dtime 
   FROM vo_order_t v
  WHERE v.item_no = '00265929'
  FETCH FIRST 1 ROW ONLY

Demo

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