我有以下问题。我使用boto3通过Amazon SES生成HMTL电子邮件。在这里我要使用占位符。我有一个列表，其中包含要在此占位符中放入的值，但我不知道如何执行此操作。每个占位符都有一个值，一切正常。
我的代码如下：
import boto3
SENDER = "xy@abc.com"
RECIPIENT = "rec@abc.com"
AWS_REGION = "yyy"
SUBJECT = "Title"
BODY_HTML = """<html>
<head></head>
<body>
<h3>Header</h3>
<p>Dear Sir,</p>
<p>please give me your feedback to these products:</p>
<p>Number: {Number},Text: {Text},Count: {Count}</p>
<p>Best regards</p>
<p>S.O</p>
<p>Company</p>
<p>S.O</p>
<p>Street and City</p>
<p>Phone</p>
<p>Fax</p>
<p>E-Mail: <a href="mailto:example@abc.com">Abcabc.com</a></p>
<p>Web: <a href="www.stackoverflow.com">www.stackoverflow.com</a></p>
</body>
</html>
"""
for x in i:
new_body = BODY_HTML.format(Number=x[3],Text=x[1],Count=x[2])
CHARSET = "UTF-8"
client = boto3.client('ses',aws_access_key_id="",aws_secret_access_key="",region_name=AWS_REGION)
try:
response = client.send_email(
Destination={
'ToAddresses': [
RECIPIENT,],},Message={
'Body': {
'Html': {
'Charset': CHARSET,'Data': new_body,'Subject': {
'Charset': CHARSET,'Data': SUBJECT,}
},Source=SENDER,)
except ClientError as z:
print(z.response['Error']['Message'])
else:
print("Email sent! Message ID:"),print(response['MessageId'])
我的列表如下：
i = [(120,'ABC',12,12345),(121,'BCD',13,253461),(122,'FFG',16,564895)]
当前输出如下：
**Header**
Dear Sir,please give me your feedback to these products:
Number: 564895,Text: FFG,Count: 16
Best regards
S.O
Company
S.O
Street and City
Phone
Fax
E-Mail: Abcabc.com
Web: www.stackoverflow.com
如何获取其他值？我想要这样的输出：
**Header**
Dear Sir,Count: 16
Number: 12345,Text: ABC,Count: 12
Number: 123461,Text: BCD,Count: 13
Best regards
S.O
Company
S.O
Street and City
Phone
Fax
E-Mail: Abcabc.com
Web: www.stackoverflow.com