在带有异步等待es6函数的变量上未定义

2024-05-09 • 问答

不知道为什么我总是对propertyAnagrams变量不明确，将不胜感激！

const anagramica = require('anagramica');

const processBody = async (generatedString,arrayOfWords) => {
  const possibleAnagrams = await anagramica.all(generatedString,(err,response) => {
    if (err) {
      console.log(`Could not find possible anagrams : ${err}`);
    }
    else {
      console.log("1",response.all);
      /// [ Array ] ///
      const array = response.all;
      console.log("2",array);
      /// [ Array ] ///
      return array;
    }
  })
  console.log("3",possibleAnagrams)
  /// undefined ///

  return { possibleAnagrams,arrayOfWords }
}

anagramica似乎没有返回Promise。如果您想使用async / await，请考虑将其转换为Promise。

const anagramica = require('anagramica');

const anagramicaPromise = generatedString => new Promise((res,rej) => {
  anagramica.all(generatedString,(err,response) => {
    if (err) {
      return rej(err);
    }
    res(response);
  }
});

const processBody = async (generatedString,arrayOfWords) => {
  try {
    const possibleAnagrams = await anagramicaPromise(generatedString);
    console.log("3",possibleAnagrams);
    return { possibleAnagrams,arrayOfWords }
  } catch(err) {
    console.log(`Could not find possible anagrams : ${err}`);
  }
}

与@Nick相同，但使用es6-promisify模块：

const { promisify } = require('es6-promisify');
const anagramica = require('anagramica');

const processBody = async (generatedString,arrayOfWords) => {
  try {
    const { all: possibleAnagrams } = await promisify(anagramica.all)(generatedString);
    return { possibleAnagrams,arrayOfWords };
  } catch (err) {
    console.log(`Could not find possible anagrams : ${err}`);
  }
};

在带有异步等待es6函数的变量上未定义

kentkent33 回答：在带有异步等待es6函数的变量上未定义

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