从我的评论中复制：

使用“作为分隔符分割后，您可以简单地提取列表中所有奇数索引的元素。然后，正常分割这些元素（使用空格分隔符），并将列表连接在一起。

示例：

text = """Lorem "ipsum dolor sit amet,consectetur adipiscing elit.". Praesent non sem urna. Pellentesque elementum "turpi'" est,"in fermentum diam auctor aliquam!". Morbi rhoncus erat ipsum,eu "tristique" """

text_split_by_quotes = text.split('"')
# get the odd-indexed elements (here's one way to do it):
text_in_quotes = text_split_by_quotes[1::2]
# split each normally (by whitespace) and flatten the list (here's one way to do it):
ans = []
for text in text_in_quotes:
    ans.extend(text.split())
# print answer
print(ans)

>>> ['ipsum','dolor','sit','amet,','consectetur','adipiscing','elit.',"turpi'",'in','fermentum','diam','auctor','aliquam!','tristique'] 

以下是两种可能的方法：

desired = [
    'ipsum','turpi\'','tristique'
    ]

text = """
Lorem "ipsum dolor sit amet,consectetur adipiscing elit.". Praesent non sem
urna. Pellentesque elementum "turpi'" est,"in fermentum diam auctor aliquam!".
Morbi rhoncus erat ipsum,eu "tristique"
"""

def extract_quoted(text):
    words = []
    next_pos = -1
    while True:
        try:
            pos = text.index('"',next_pos + 1)
        except ValueError:
            break
        try:
            next_pos = text.index('"',pos + 1)
        except ValueError as e:
            raise ValueError("mismatched quotes") from e
        quoted_segment = text[pos + 1:next_pos]
        words.extend(quoted_segment.split())
    return words

def split_only(text):
    return [word for chunk in text.split('"')[1::2] for word in chunk.split()]

if __name__ == "__main__":
    print(extract_quoted(text) == desired)
    print(split_only(text) == desired)

第一个是更明确地说明文本的形式 “解析”，而第二个可能更多是基于浮华的单行拆分 您正在寻找的方法。

我尝试过：

a = """Lorem "ipsum dolor sit amet,eu "tristique" """
in_quote = 0
res = []
word = ''

for i in a:
    if i == '"':
        in_quote = 1 - in_quote
        if word:
            res+=[word]
            word = ''
    elif in_quote:
        if i == ' ':
            res+=[word]
            word = ''
        else:
            word+=i
print(res)

检查一下这种逻辑，基本上是在拆分之后，您可以选择第二个索引，因为您开始时在文本中没有双引号。

text = 'Lorem "ipsum dolor sit amet,consectetur adipiscing elit.". Praesent non sem urna. Pellentesque elementum "turpi" est,eu "tristique"'
print(text)

split_text = text.split('"')
print(split_text)

new_split_text = [elem for i,elem in enumerate(split_text) if i%2 == 1]
print(new_split_text)

如果您要一支衬板：

new_split_text = [elem for i,elem in enumerate(text.split('"')) if i%2 == 1]

输出：

['ipsum dolor sit amet,consectetur adipiscing elit.','turpi','in fermentum diam auctor aliquam!','tristique']