是否有任何简单的方法可以将32位寄存器的值分别分成2个带符号的16位短裤？
我想到了这个
#t0 holds the 32bit value containing the 2 signed shorts
sra $v0,$t0,16 #extract the 1st signed short and put it in v0
li $t1,0xffff #create a mask
and $v1,$t1 #extract the 2nd signed short and put it in v1
但这会破坏第二个值的符号，对吗？有没有一种简单的方法不涉及屏蔽另一个寄存器中的2个值的符号并将其移到v1之后？