PHP从具有相同名称的xml节点提取数据

我正在尝试从具有深节点结构的审阅xml文件中提取值。我需要从父节点“ reviews-> reviews”和子节点“ rating”中提取数据,其中“ questionGroup” =“ DEFAULT_OPINION”。我尝试了几种代码变体,但搜索了很长时间后找不到找到两个值的解决方案。

这是xml文件的一部分:

<reviews>
  <reviews>
    <reviewId>f46f317c-5009-4ec4-ac8d-2b173db2dde6</reviewId>
    <reviewAuthor>K.</reviewAuthor>
    <city>Haarlem </city>
    <rating>10</rating>
      <reviewContent>
        <reviewContent>
            <questionGroup>DEFAULT_OVERALL</questionGroup>
            <questionType>INT</questionType>
            <rating>10</rating>
            <order>0</order>
            <questionTranslation>Totaal score</questionTranslation>
        </reviewContent>
        <reviewContent>
            <questionGroup>DEFAULT_ONELINER</questionGroup>
            <questionType>TEXT</questionType>
            <rating>Perfecte service en mooie kwaliteit bord. </rating>
            <order>0</order>
            <questionTranslation>Beschrijf uw ervaring in een regel</questionTranslation>
        </reviewContent>
        <reviewContent>
            <questionGroup>DEFAULT_OPINION</questionGroup>
            <questionType>TEXT</questionType>
            <rating>
            De service is perfect. Tijdens het bestelproces werden mijn vragen beantwoord middels chat berichtjes via de website. Het bord werd netjes verpakt geleverd en is van mooie                 kwaliteit. Erg blij mee.
            </rating>
            <order>0</order>
            <questionTranslation>Beschrijf uw ervaring</questionTranslation>
        </reviewContent>
        <reviewContent>
            <questionGroup>DEFAULT_RECOMMEND</questionGroup>
            <questionType>BOOLEAN</questionType>
            <rating>true</rating>
            <order>0</order>
            <questionTranslation>Aanbevelen?</questionTranslation>
        </reviewContent>
  </reviews>
<reviews>

这是我当前的代码:

<?php
$xml = simplexml_load_file("https://www.kiyoh.com/v1/review/feed.xml?hash=bhokkolsgogtaf9");
$reviewContents = $xml->xpath('//reviewContent[questionGroup="DEFAULT_OPINION"]/rating');

foreach ($xml->reviews->reviews as $review){
          echo '<div class="kiyoh-shop-snippets"  style="{$show_rating|escape:"htmlall":"UTF-8"}"><div class="rating-box"><div class="rating"  style="width:' . ($review->rating*10) . '%"></div></div></div>';
    echo 'Naam: '.$review->reviewAuthor.'<br>';
    echo 'Woonplaats: '.$review->city.'<br>';
    echo 'Review: '.$review->reviewContent->reviewContent->rating.'<br>';
}
?>

我也尝试过:

<?php
$xml = simplexml_load_file("https://www.kiyoh.com/v1/review/feed.xml?hash=bhokkolsgogtaf9");

  foreach($xml->xpath('//reviewContent') as $item) {

    $row = simplexml_load_string($item->asXML());
    $v = $row->xpath('//questionGroup[. ="DEFAULT_OPINION"]');
    if($v[0]){
        print $item->reviewAuthor.'<br>';
        print $item->city.'<br>';
        print $item->rating.'<br>';
    }

}
?>

在第一个代码中,我从第一个节点获得名称和城市以及等级的结果。在第二个代码中,我得到要显示为等级值的评论,而不是父节点数据。如何获得此评论数据以及第一个代码的结果?

Linpeipei1985 回答:PHP从具有相同名称的xml节点提取数据

您必须遍历您的评论内容,并添加条件以获取特定问题组类型的评论

<?php
$xml = simplexml_load_file("https://www.kiyoh.com/v1/review/feed.xml?hash=bhokkolsgogtaf9");
foreach ($xml->reviews->reviews as $review) {
  echo '<div class="kiyoh-shop-snippets"  style="{$show_rating|escape:"htmlall":"UTF-8"}"><div class="rating-box"><div class="rating"  style="width:' . ($review->rating * 10) . '%"></div></div></div>';
  echo 'Naam: ' . $review->reviewAuthor . '<br>';
  echo 'Woonplaats: ' . $review->city . '<br>';
  foreach ($review->reviewContent->reviewContent as $content) {
    if ($content->questionGroup == 'DEFAULT_OPINION') {
      echo 'Review: ' . $content->rating . '<br>';
    }
  }
}
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