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按Inspector_ID分组的总和，以熊猫为单位的天

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我有一个数据框，如下所示。这是两个检查员在不同日期所经过的距离。

Inspector_ID      Timestamp                  Distance
    1              2018-07-24 7:31:00          0
    1              2018-07-24 7:31:01          2.3
    1              2018-07-24 7:33:01          2.8
    1              2018-07-25 7:32:04          0
    1              2018-07-25 7:33:06          3.6
    2              2018-07-20 8:35:08          0
    2              2018-07-20 8:36:10          5.6
    2              2018-07-20 8:37:09          2.1
    2              2018-07-27 8:38:00          0
    2              2018-07-27 8:39:00          3
    2              2018-07-27 8:40:00          2.6

从上面，我想在数据框下面准备

预期产量

Inspector_ID   Day_of_the_month   Total_distance   No.of_entries_in that_day  week_of_the_month
1              24                 5.1              3                          4
1              25                 3.6              2                          4
2              20                 7.7              3                          3
2              27                 5.6              3                          4
li57268631 回答：按Inspector_ID分组的总和，以熊猫为单位的天
    import pandas as pd

    from datetime import datetime as dt
    df={"Inspector_ID":[1,1,2,2],"Timestamp" :["2018-07-24 7:31:00","2018-07-24 7:31:01","2018-07-24 7:33:01","2018-07-25 7:32:04","2018-07-25 7:33:06","2018-07-20 7:31:00","2018-07-20 8:36:10","2018-07-20 8:37:09","2018-07-27 8:38:00","2018-07-27 8:39:00","2018-07-27 8:38:00"],"Distance":[0,2.3,2.8,3.6,5.6,2.1,3,2.6]}

    df["Day"]=[]
    df["week_of_month"]=[]

    for entry in df["Timestamp"]:  
        df["Day"].append(dt.strptime(entry,'%Y-%m-%d %H:%M:%S').day)
        df["week_of_month"].append((dt.strptime(entry,'%Y-%m-%d %H:%M:%S').day - 1) // 7 + 1)

    df=pd.DataFrame(df)

    result=df.groupby(['Inspector_ID','Day','week_of_month'])['Distance'].agg({"totdist":"sum","NoEntries":"count"})
    print(result)
datetimepandaspandas-groupby
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