如果将提供的格式不正确的文档更正，请用等价的字符实体引用>>> step_1 ['Gourds','watermelon','Post','pounder','calf','hay','or','duck','is','tool','shed','horse','In','eggplant','quonset','grain','bins','trucks','pole','with','fences','gates','zucchini','carrots','scrap','metal','Peacocks','baa','ostriches','owls','Kidney','beans','ostrich','Gourds','utters','at','welding','equipment','a','oink','haybine','Apples','ducks','straw','quail','donkey','hook','cucumbers','Combine','Harvester','swather','baler','as','parsley','melon','in','ha.\n'] 替换未定义的实体 ：

 

然后这个XPath表达式：

<table border="1" class="class_table"> <tbody> <tr class="class_tr"> <td class="class_td">&#xA0;</td> </tr> <tr class="class_tr"> <td class="class_td"><span class="class_span_ok"></span>square</td> </tr> <tr class="class_tr"> <td class="class_td"><span class="class_span_ko"></span>circle</td> </tr> <tr class="class_tr"> <td class="class_td"><span class="class_span_ok"></span>triangle</td> </tr> </tbody> </table>

在评估时，会精确选择所需的/*/*/*/td [@class='class_td' and not(span[@class='class_span_ko']) and normalize-space(translate(.,' ','')) ]/> 元素：

td

基于XSLT的验证

此转换对上面的XPath表达式求值，并将所选元素复制到输出：

<td class="class_td">
   <span class="class_span_ok"/>square</td>
<td class="class_td">
   <span class="class_span_ok"/>triangle</td>

产生了所需的正确结果：

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

  <xsl:template match="/">
    <xsl:copy-of select=
    "/*/*/*/td
        [@class='class_td'
        and not(span[@class='class_span_ko'])
        and normalize-space(translate(.,''))
        ]"/>
  </xsl:template>
</xsl:stylesheet>

注意：

如果仅需要所需元素的字符串值，则XPath表达式可以是：

<td class="class_td">
   <span class="class_span_ok"/>square</td>
<td class="class_td">
   <span class="class_span_ok"/>triangle</td>