使用Discord Python报告命令

2024-05-03 • 问答

我正在尝试创建一个将消息发送到通道的报告命令。例如* report username＃1234推理放在这里等等等

频道由{作者}报告的{用户}收到{原因}。并向作者发送了一条私人消息，告诉他们报告通过了。

但是，如果所报告的用户具有“踢”权限，则其也会发送到第二个频道。并私下发送给我所有者的消息。与{作者}为{原因}报告的{用户}的结构相同。

但是...我不断收到一些奇怪的错误，例如未定义的bot（即使已定义）。

    async def report(self,ctx,user,*,reason=None):
        logger = bot.get_channel(644966241835941898)
        channel = bot.get_channel(641639710183129113)
        if reason is None:
            await ctx.author.send('Hey I get that you are trying to report someone but I need a reason. Please try again.')
        elif ctx.message.author.guild_permissions.read_messages:
            await ctx.channel.send(f'{user} reported by {author} for {reason}')
        elif user.guild_permissions.kick_members:
            await ctx.logger.send(f'{user},reported by {author} for {reason}')
            await ctx.channel.send(author,reason)
            await ctx.author.send("""Im going to put this in a safe spot for the wizard himself to review.""")```

async def report(self,ctx,user : discord.Member,*reason) channel = self.bot.get_channel(your channel id) #since it's a cog u need self.bot author = ctx.message.author rearray = ' '.join(reason[:]) #converts reason argument array to string if not rearray: #what to do if there is no reason specified await channel.send(f"{author} has reported {user},reason: Not provided") await ctx.message.delete() #I would get rid of the command input else: await channel.send(f"{author} has reported {user},reason: {rearray}") await ctx.message.delete()

使用Discord Python报告命令

morenming 回答：使用Discord Python报告命令

额外

使用Discord Python报告命令

morenming 回答：使用Discord Python报告命令

额外

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