我正在用字符串javascript逐字写逻辑。
但是我认为我的代码更长，所以我正在寻找好的答案。
Ex :- I/p- Hi how are you // o/p- iH woh era uoy
<script>
function ReverseString(val) {
var op = "",iCount = -1;
for (let i = 0; i <= val.length; i++) {
if (val[i] != " " && i != val.length)
continue;
for (let j = i - 1; j > iCount; j--)
op += val[j];
if (i != val.length)
op += " ";
iCount = i;
}
return op;
}
console.log(ReverseString("Hi how are you"));
</script>
一种方法是按空格将字符串拆分为一个单词数组，然后使用map()反转数组中的单词，如下所示：
function ReverseString(val) {
return val.split(/\s/g).map(w => w.split('').reverse().join('')).join(' ');
}
console.log(ReverseString("Hi how are you"));,
您的解决方案。
<script>
rev=(val)=>{
return val.split("").reverse().join("").split(" ").reverse().join(" ")
}
console.log(rev('Hi how are you'))
</script>,
一种方法是使用split（）将您的单词分隔成一个数组
然后为每个单词拆分字母并使用反向功能，然后重新加入它们。
至少，重新加入单词
const str = "Hi how are you";
let str_reversed = str.split(' ');// put each word in an array
str_reversed = str_reversed.map(word => word.split('').reverse().join('')); // for each word,we put each letter in array,reverse them and then re-join them
str_reversed = str_reversed.join(' '); // rejoin the word
console.log(str_reversed);,
一种单行解决方案，以颠倒每个单词的顺序：
var original = 'Hi how are you';
var reversed = original.split("").reverse().join("").split(" ").reverse().join(" ")
o / p：“ iH woh age uoy”
,select *,case when f.FeaturedUntil is not null THEN f.PurchasedAt else NULL end AS PurchasedAtNew
from Items i
left join Feature f on i.Id = f.ItemId
order by PurchasedAtNew desc,i.Id