如何以编程方式JHipster Springboot配置?

我已经尝试过自动装配SpringBootConfiguration,但是在我的测试项目中什么也没找到。在执行一些测试之前,我需要检查在application-dev.properies中添加的字段,并查看其正确还是错误。

fengziyun 回答:如何以编程方式JHipster Springboot配置?

有人回答过:

Where and How To Define An Application Property? - JHIpster

但是请注意取消注释

package com.example.empireuslforms;

import androidx.appcompat.app.AppCompatActivity;

import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;


public class GeneralEmailActivity extends AppCompatActivity {

    public EditText mEmailText;
    public Button mSendEmail;
    public TextView mUserName;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_general_email);

        mUserName = (TextView)findViewById(R.id.tvUser);
        mEmailText = (EditText)findViewById(R.id.etEmailText);
        mSendEmail = (Button)findViewById(R.id.btnEmailSend);
        mSendEmail.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                sendMail();
            }
        });


    }

    private void sendMail() {

        String user_name = mUserName.getText().toString();
        String mail = "email@email.com";
        String message = "From: " + user_name + "\n" + mEmailText.getText().toString();
        String subject = "Empire Forms App Contact";

        //Send Email
        JavaMailAPI javaMailAPI = new JavaMailAPI(this,mail,subject,message);

        javaMailAPI.execute();
    }
}

在属性文件中。并且最好创建一个对象,并确保自己实例化该对象,因此它不为null。如图所示,它应该是最终对象。

在此处找到另一个示例:https://github.com/jhipster/jhipster/blob/master/jhipster-framework/src/main/java/io/github/jhipster/config/JHipsterProperties.java

本文链接:https://www.f2er.com/3111379.html

大家都在问