我正在启动一个程序，您必须在其中选择一种模式，一种操作，然后它将为您计算。仍在进行中。

但是，如果您输入“ A”或“ B”，它会起作用，而当您输入“符号”或操作时，它也会起作用。但是，在用户输入符号后，它将完成程序并退出代码。

我需要有关这种情况的一些反馈意见：

我的最终目标是让程序也要求用户输入他们想要计算的数字，但是程序不要求用户输入。我觉得好像这个问题必须处理浮点数（输入，elif s'（如果是其他情况），或者它如何卡在函数的参数中。

 import fractions
print("Welcome to Advanced Calculator Version 1.01")
module = input("Enter a mode,for example; 1NUMber_OPERATIONS [A],or 2NUMber_OPERATIONS [B]")
if module == "A":
    operation = input('Enter an operation,for example; sq_rt,fraction,percent,round')
elif module == "B":
    operation = input('Enter an operation,for example; -,+,*,/,^')


def doublecheck():
#OPERATION|||MODESA
    if operation == "-":
        num1 = float(input("Enter a number: "))
        num2 = float(input("Enter another number: "))
        result= num1 - num2
        print(result)
    elif operation == "+":
        num1 = float(input("Enter a number: "))
        num2 = float(input("Enter another number: "))
        result= num1 + num2
        print(result)
    elif operation == "*":
        num1 = float(input("Enter a number: "))
        num2 = float(input("Enter another number: "))
        result= num1 * num2
        print(result)
    elif operation == "/":
        num1 = float(input("Enter a number: "))
        num2 = float(input("Enter another number: "))
        result= num1 / num2
        print(result)
    elif operation == "^":
        num1 = float(input("Enter a number: "))
        num2 = float(input("Enter another number: "))
        result= num1^num2
        print(result)
    elif operation == "sq_rt":
        num1 = float(input("Enter a number: "))
        num_sqrt = num1 ** 0.5
        print('The square root of %0.3f is %0.3f' % (num1,num_sqrt))
    elif operation == "fraction":
        num1 = float(input("Enter a number: "))
        str(fractions.Fraction(num1))
    elif operation == "percent":
        num1 = float(input("Enter a number: "))
        v = 100
        percent= num1 * v
        print(percent + "%")
    elif operation == "round":
        num1 = float(input("Enter a number: "))
        round(num1)
return 0