我有以下代码显示矩阵的乘积
但是我想要的是使用split通过一个函数编写此代码。我尝试了很多次,但是我不知道该怎么做。 这是显示矩阵乘法的C#代码。
首先,我创建一个线程。然后,我启动并加入线程,它显示了,但是我使用的方式太长了,如果有人知道我该怎么办,我想简短些。
Thread Row1Col1 = new Thread(R1C1);
Thread Row1Col2 = new Thread(R1C2);
Thread Row2Col1 = new Thread(R2C1);
Thread Row2Col2 = new Thread(R2C2);
Thread Row3Col1 = new Thread(R3C1);
Thread Row3Col2 = new Thread(R3C2);
Row1Col1.Start();
Row1Col1.Join();
Row1Col2.Start();
Row1Col2.Join();
Row2Col1.Start();
Row2Col1.Join();
Row2Col2.Start();
Row2Col2.Join();
Row3Col1.Start();
Row3Col1.Join();
Row3Col2.Start();
Row3Col2.Join();
Console.ReadLine();
}
static void R1C1()
{
int mt3 = 0;
int[] mt1 = { 1,2,3 };
int[] mt2 = { 10,7,2 };
for (int i = 0; i < mt1.Length; i++)
{
mt3 += mt1[i] * mt2[i];
}
Console.Write(mt3);
}
static void R1C2()
{
int[] mt1 = { 1,3 };
int[] mt2 = { 11,5,4 };
int mt4 = 0;
for (int i = 0; i < mt1.Length; i++)
{
mt4 += mt1[i] * mt2[i];
}
Console.Write(" " + mt4);
Console.WriteLine();
}
static void R2C1()
{
int[] mt1 = { 4,6 };
int[] mt2 = { 10,2 };
int mt5 = 0;
for (int i = 0; i < mt1.Length; i++)
{
mt5 += mt1[i] * mt2[i];
}
Console.Write(mt5);
}
static void R2C2()
{
int[] mt1 = { 4,6 };
int[] mt2 = { 11,4 };
int mt6 = 0;
for (int i = 0; i < mt1.Length; i++)
{
mt6 += mt1[i] * mt2[i];
}
Console.Write(" " + mt6);
Console.WriteLine();
}
static void R3C1()
{
int[] mt1 = { 1,3,2 };
int[] mt2 = { 10,2 };
int mt7 = 0;
for (int i = 0; i < mt1.Length; i++)
{
mt7 += mt1[i] * mt2[i];
}
Console.Write(mt7);
}
static void R3C2()
{
int[] mt1 = { 1,2 };
int[] mt2 = { 11,4 };
int mt8 = 0;
for (int i = 0; i < mt1.Length; i++)
{
mt8 += mt1[i] * mt2[i];
}
Console.Write(" " + mt8);
}