我有以下Hibernate查询：

String HSQL = "from Page as p "
  + "where not exists (from Link as l where l.dealId = p.id) "
  + "and p.userId = :userId";

return (List<Deal>) sessionFactory.getcurrentSession()
  .createQuery(HSQL)
  .setParameter("userId",userId)
  .list();

但是在方法.createQuery(HSQL)上，它失败，并带有以下异常

[ ERROR ] [12.11.2019 13:19:10] --- U: I: S: --- org.hibernate.hql.internal.ast.ErrorTracker: line 1:137: unexpected token: .
[ ERROR ] [12.11.2019 13:19:10] --- U: I: S: --- org.hibernate.hql.internal.ast.ErrorTracker: line 1:137: unexpected token: .
antlr.NoViableAltException: unexpected token: .
    at org.hibernate.hql.internal.antlr.HqlBaseParser.fromClassOrOuterQueryPath(HqlBaseParser.java:1972) [hibernate-core-5.4.1.Final.jar:5.4.1.Final]
    at org.hibernate.hql.internal.antlr.HqlBaseParser.fromRange(HqlBaseParser.java:1499) [hibernate-core-5.4.1.Final.jar:5.4.1.Final]
    at org.hibernate.hql.internal.antlr.HqlBaseParser.fromClause(HqlBaseParser.java:1343) [hibernate-core-5.4.1.Final.jar:5.4.1.Final]
    at org.hibernate.hql.internal.antlr.HqlBaseParser.selectFrom(HqlBaseParser.java:1063) [hibernate-core-5.4.1.Final.jar:5.4.1.Final]
    at org.hibernate.hql.internal.antlr.HqlBaseParser.queryRule(HqlBaseParser.java:748) [hibernate-core-5.4.1.Final.jar:5.4.1.Final]
    at org.hibernate.hql.internal.antlr.HqlBaseParser.subQuery(HqlBaseParser.java:3910) [hibernate-core-5.4.1.Final.jar:5.4.1.Final]
    at org.hibernate.hql.internal.antlr.HqlBaseParser.quantifiedExpression(HqlBaseParser.java:3515) [hibernate-core-5.4.1.Final.jar:5.4.1.Final]
    at org.hibernate.hql.internal.antlr.HqlBaseParser.unaryExpression(HqlBaseParser.java:3373) [hibernate-core-5.4.1.Final.jar:5.4.1.Final]
    at org.hibernate.hql.internal.antlr.HqlBaseParser.multiplyExpression(HqlBaseParser.java:3273) [hibernate-core-5.4.1.Final.jar:5.4.1.Final]
...

我的Hibernate版本是5.4.1。

查询出了什么问题？