使用每个视图在数据库上创建check_box并放置值和ID

2024-05-03 • 问答

我正在尝试为数据库中的每个ID显示一个复选框，这可能对我有帮助。按照我的代码尝试，但在同一check_box =“ id：1”，check_box“ id：2”中显示多个复选框

我想这样显示

<td> check_box="id1" value="false"</td> 
<td> check_box="id2" value="true"</td>

如果要使用一个复选框，我也希望这样做此已在Rails控制台上提交表单上选中：

Parameters: {"utf8"=>"✓","authenticity_token"=>"b3kaOUAgyJHqho70958585SVSv7a1Eo3Yd2z54=","@search_inactive"=>"30","true"}

Parameters: {"utf8"=>"✓","authenticity_token"=>"b3kaOUAgyJHqho70958585Sassaffdaaz=","@search_inactive"=>"29","false"}

我的视图：

<tr>
<td>
 <%= link_to "Answer","https://docs.google.com/forms/d/1WdpuW2pD-bqhlSmC77sWb3_nz56NAF-kHSh5--GkLnY/edit",:target => "_blank",:class => "btn_forms_gf" %>
  <td align="center">
  <%= form_for :app_changes,:url => {:controller => :user,:action => :show_search } do |f| %>
  <% @search_inactive.each do |p| %>
  <%= check_box_tag "@search_inactive",{},p.id %>
  <% end %>
  <%= link_to_function('Disable',"$('form').submit()",:app_changes => @show_search,:class => "btn_save") %>
  <% end %>
  </td>
  </tr>
<% end %>
<% end %>

“我的控制器”将呈现所有搜索无效和有效的页面

     def show_search
       @show_search_active = Search.find_by_sql("select * from search where active is true")
       @show_search_inactive = Search.find_by_sql("select * from search where active is false")
   render('/users/show_search_users',:layout => true)
   end

<%= form_for ...%> <% @search_inactive.each do |p| %> <%= hidden_field_tag "search_inactive[#{p.id}]",false %> <%= check_box_tag "search_inactive[#{p.id}]",true %> <% end %> <% @search_active.each do |p| %> <%= hidden_field_tag "search_active[#{p.id}]",false %> <%= check_box_tag "search_active[#{p.id}]",true,true %> # true here to have it checked by default <% end %> <% end %>

{ "search_inactive"=>{"2"=>"false","4"=>"false","71"=>"false","72"=>"false","73"=>"false","74"=>"false"},"search_active"=>{"102"=>"true","104"=>"true","171"=>"true","172"=>"true","173"=>"true","174"=>"true"} }

使用每个视图在数据库上创建check_box并放置值和ID

kchuan 回答：使用每个视图在数据库上创建check_box并放置值和ID

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