具有ExecutorService池的数组中所有元素的总和不起作用

我试图了解ExecutorService,我想对数组的所有元素求和。我做了两种方法,一种使序列求和(只是一个for循环,将所有元素求和),另一种与池并发。我的问题是,使用ExecutorService的总金额几乎总是与序列总金额不符,有时甚至是一个。

package sumArregloConc;

import java.util.Random;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.atomic.AtomicInteger;

public class SumaArregloMain {

    private final static int cantElem = 1000;
    private static ExecutorService tpool = Executors.newCachedThreadPool();



    public static void main(String[] args)
    {

        int[] arreglo = generarArreglo(cantElem); //generate the array with random numbers

        System.out.println(sumaSerial(arreglo));
        System.out.println(sumaConcurrente(arreglo));
    }

    public static int sumaSerial(int[] arreglo)
    {
        int suma = 0;
        for(int i =0; i< arreglo.length; i++)
        {
            suma += arreglo[i];
        }

        return suma;

    }

    public static int sumaConcurrente(int[] arreglo)
    {
        AtomicInteger total = new AtomicInteger(0);

        for(int i = 1 ; i < cantElem; i++){

            int a = arreglo[i];
                Thread thread = new Thread(new Runnable(){
                    public void run() {
                        int res = a;
                        total.addAndGet(res);
                        return;
                }});
                tpool.submit(thread);
        }

        tpool.shutdown(); //wait for everything to finish
        return total.get();
    }

    public static int[] generarArreglo(int cantElem)
    {
        int[] arreglo = new int[cantElem];
        Random rand = new Random();

        for(int i = 0; i < cantElem; i++)
        {
            arreglo[i] = rand.nextInt(10);
        }

        return arreglo;
    }
}

有人可以说出什么问题吗?

cz289548699 回答:具有ExecutorService池的数组中所有元素的总和不起作用

发现错误。首先,埃里克(Eric)关于awaitTermination和Runnable所说的,但主要的错误只是循环从i = 1而不是i = 0开始,这是愚蠢的错误。

    public static int sumaConcurrente(int[] arreglo)
    {
        AtomicInteger total = new AtomicInteger(0);

        for(int i = 0 ; i < cantElem; i++){

            int a = arreglo[i];

            tpool.submit(new Runnable(){
                public void run() {
                    total.addAndGet(a);
                    return;
                    }
                });
        }

        tpool.shutdown(); //wait for everything to finish
        try {
              tpool.awaitTermination(Long.MAX_VALUE,TimeUnit.NANOSECONDS);
            } catch (InterruptedException e) {  
            }
        return total.get();
    }
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