我想要插入函数来生成字符序列，但是无法编写或搜索它。

我尝试使用https://www.tutorialspoint.com/cplusplus-program-to-generate-a-sequence-of-n-characters-for-a-given-specific-case，但是它对我不起作用，并且出现“段错误”。

我已经使用过类似的基金，但是上面的解决方案却给我带来了段错误。

    string = salt,b_salt,outTrip,buffer;
    string dict = ".012345678A:;<=>?@BCDEFGHIJKLMNOPQRSTUVWXY[\\]^_`ZabcdefghijklmnopqrstuvwxyzT"
    for(i = 0; i < n; i++)
    {
        buffer = generateSeq(dict)
        b_salt = buffer;
        b_salt += "...";

        salt = b_salt.substr(1,2);
        s_test = crypt(buffer.c_str(),salt.c_str());

        outTrip = s_test;

        cout << seq << "\t\t\t" << outTrip << endl;

我的代码：

#include <iostream>
#include <unistd.h>
#include <cstring>

using namespace std;

void GenSequence(char str[],int m,int len,char *seq)
{
    int i,j=0,k,index,r;
    for(i = 0; i < m; i++)
    {
        if(j == 0) {
            seq[j++] = str[rand()%len];}
        else
        {
            h:
            index = rand()%len;
            for(k = 0; k < j; k++)
            {
                if(str[index] == seq[k])
                    goto h;
            }
            seq[j++] = str[index];
        }
    }
    seq[j] = '\0';
}

int main() 
{   
    int n,m,len,i;
    char str[] = {46,48,49,50,51,52,53,54,55,56,65,58,59,60,61,62,63,64,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,91,92,93,94,95,96,90,97,98,99,100,101,102,103,104,105,106,107,108,109,110,111,112,113,114,115,116,117,118,119,120,121,122};
    n = 1000;
    m = 7;
    len = strlen(str);
    string trip,match = "shi",buf,salt;
    char seq[m];
    for(i = 0; i < n; i++)
    {
        outTrip = "";
        GenSequence(str,seq);
        b_salt = seq;
        b_salt += "...";

        salt = b_salt.substr(1,2);
        outTrip = crypt(seq,salt.c_str());


        cout << seq << "\t\t\t" << outTrip << endl;

    }
}

解决方案： 我删除了一些错误的字符，即 字符串字典=“ .0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz”; 对我有用。