是否可能存在Comparator的身份表示？

在寻找简化Removing overloaded method in Java中代码的过程中，我想到了这一点，并得出结论，如果每次比较都导致对象相等，则顺序实际上不会改变，从而使操作成为 identity 。因此，我最终得到了这样一个（效率低下的）建议：

public static <T,G> List<G> toListOfNewType(List<T> inputList,Function<T,G> mapperFunction) {
    return toListOfNewType(inputList,mapperFunction,(a,b) -> 0); // overloaded with comparator for 'G' type
}

但是我现在想知道的是，这是否也适用于具有自定义compareTo实现的对象？给定Stream实现，假设这样做真的安全吗？

编辑：我尝试过并保留了顺序的某些测试如下：

List<Integer> integers = List.of(1,3,45356,47424,34234,4,234234,234,-23,-34);
System.out.println(integers);
System.out.println(integers.stream().sorted((a,b) -> 0).collect(Collectors.toList()));
System.out.println(integers.stream().sorted((a,b) -> 0).parallel().collect(Collectors.toList()));

[1,-34]
[1,-34]

List<String> strings = List.of("aadad","Z","vsadasd","zadad","C","Aadasd");
System.out.println(strings);
System.out.println(strings.stream().sorted((a,b) -> 0).collect(Collectors.toList()));
System.out.println(strings.stream().sorted((a,b) -> 0).parallel().collect(Collectors.toList()));

[aadad,Z,vsadasd,zadad,C,Aadasd]
[aadad,Aadasd]

Set<Integer> integerSet = Set.of(1,-34);
System.out.println(integerSet);
System.out.println(integerSet.stream().sorted((a,b) -> 0).parallel().collect(Collectors.toList()));
System.out.println(integerSet.stream().sorted((a,b) -> 0).collect(Collectors.toList()));

[-34,1,0]
[-34,0]

Set<String> stringSet = Set.of("aadad","Aadasd");
System.out.println(stringSet);
System.out.println(stringSet.stream().sorted((a,b) -> 0).collect(Collectors.toList()));
System.out.println(stringSet.stream().sorted((a,b) -> 0).parallel().collect(Collectors.toList()));

[zadad,Aadasd,aadad]
[zadad,aadad]