我想建立组织结构图。如下所示:
A - B - C
B - C - D
A - E
这意味着A监督B,B监督C,C监督D,而A监督E。我想知道是否可以通过将每个员工用作节点来构建树图。
A - B - C - D
|
E
一些代码如下,我不知道如何将其应用于我当前的人力资源数据。
pip install python-igraph
import igraph
from igraph import Graph,EdgeSeq
nr_vertices = 25
v_label = list(map(str,range(nr_vertices)))
G = Graph.Tree(nr_vertices,2) # 2 stands for children number
lay = G.layout('rt')
position = {k: lay[k] for k in range(nr_vertices)}
Y = [lay[k][1] for k in range(nr_vertices)]
M = max(Y)
es = EdgeSeq(G) # sequence of edges
E = [e.tuple for e in G.es] # list of edges
L = len(position)
Xn = [position[k][0] for k in range(L)]
Yn = [2*M-position[k][1] for k in range(L)]
Xe = []
Ye = []
for edge in E:
Xe+=[position[edge[0]][0],position[edge[1]][0],None]
Ye+=[2*M-position[edge[0]][1],2*M-position[edge[1]][1],None]
labels = v_label
import plotly.graph_objects as go
fig = go.Figure()
fig.add_trace(go.Scatter(x=Xe,y=Ye,mode='lines',line=dict(color='rgb(210,210,210)',width=4),hoverinfo='none'
))
fig.add_trace(go.Scatter(x=Xn,y=Yn,mode='markers',name='bla',marker=dict(symbol='circle-dot',size=28,color='#6175c1',#'#DB4551',line=dict(color='rgb(50,50,50)',width=1)
),text=labels,hoverinfo='text',opacity=0.8
))
def make_annotations(pos,text,font_size=15,font_color='rgb(250,250,250)'):
L=len(pos)
if len(text)!=L:
raise ValueError('The lists pos and text must have the same len')
annotations = []
for k in range(L):
annotations.append(
dict(
text=labels[k],# or replace labels with a different list for the text within the circle
x=pos[k][0],y=2*M-position[k][1],xref='x1',yref='y1',font=dict(color=font_color,size=font_size),showarrow=False)
)
return annotations
axis = dict(showline=False,# hide axis line,grid,ticklabels and title
zeroline=False,showgrid=False,showticklabels=False,)
fig.update_layout(title= 'Tree with Reingold-Tilford Layout',annotations=make_annotations(position,v_label),font_size=12,showlegend=False,xaxis=axis,yaxis=axis,margin=dict(l=40,r=40,b=85,t=100),hovermode='closest',plot_bgcolor='rgb(248,248,248)'
)
fig.show()
我不知道圆圈中的数字如何显示。相反,我希望在圈子中显示员工的姓名。 有人可以帮忙吗?